Calculating Initial Velocity Needed to Reach Specified Height

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Homework Help Overview

The discussion revolves around calculating the initial velocity required for a projectile to reach a specified height within a given time frame, specifically in a vertical motion context. The problem involves understanding the effects of gravity on the projectile's motion and how to manage velocity updates over discrete time intervals.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of kinematic equations to derive initial velocity based on displacement, time, and acceleration due to gravity. There are attempts to calculate the initial velocity and questions about how to decrement velocity over time intervals. Some participants express confusion regarding the relationship between the calculated initial velocity and the required conditions for reaching the specified height at the specified time.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some have provided calculations and suggestions for updating velocity, while others question the validity of these approaches and whether adjustments to acceleration are necessary to meet the problem's requirements.

Contextual Notes

Participants note the need for the projectile to reach a height of 1 meter in exactly 0.25 seconds, raising concerns about the adequacy of the initial velocity and the effects of gravity. There is also mention of the need to account for the number of updates per second in the velocity calculations.

goombachu
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Homework Statement



I have a projectile that shoots straight up into the air (parallel to the y-axis). I need to calculate the initial velocity needed to reach a specific height. I am given the following:
- the y-displacement (s1) to reach
- the time (t) at which the projectile reaches the specified height
- the acceleration due to gravity (a = -9.8 m/s/s)

Additionally, after time (t), velocity should be zero, and the projectile should be at the specified height. In other words, it takes (t) seconds to reach the "apex."

Homework Equations



Nothing given, but I suspect:
s1 = s0 + (v0 * t) + (0.5 * a * t * t)

The Attempt at a Solution



Let's say:
- s0 = 0 meters
- s1 = 1 meters
- t = 0.25 secs
- a = -9.8 m/s/s
- v0 = ?

I thought I'd solve for v0 in the equation above. That gives:

v0 = s1 / t - (0.5 * a * t)
v0 = 1 / 0.25 - (0.5 * -9.8 * 0.25)
v0 = 4 - (-1.225)
=> v0 = 5.1225

That seems valid, but now let's say I need to update the velocity 30 times per second. This means that I am starting with an initial velocity of 5.1225 m/s, and each "tick" I need to decrement the velocity by some amount. After 0.25 seconds my velocity should tick down to zero.

I am guessing I would use (v1 = v0 + a * t) per "tick" for this, correct? Where v0 is always 5.1225 and (t) increments by (1/30) in each tick?
 
Last edited:
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goombachu said:

Homework Statement



I have a projectile that shoots straight up into the air (parallel to the y-axis). I need to calculate the initial velocity needed to reach a specific height. I am given the following:
- the y-displacement (s1) to reach
- the time (t) at which the projectile reaches the specified height
- the acceleration due to gravity (a = -9.8 m/s/s)

Additionally, after time (t), velocity should be zero, and the projectile should be at the specified height. In other words, it takes (t) seconds to reach the "apex."

Homework Equations



Nothing given, but I suspect:
s1 = s0 + (v0 * t) + (0.5 * a * t * t)

The Attempt at a Solution



Let's say:
- s0 = 0 meters
- s1 = 1 meters
- t = 0.25 secs
- a = -9.8 m/s/s
- v0 = ?

I thought I'd solve for v0 in the equation above. That gives:

v0 = s1 / t - (0.5 * a * t)
v0 = 1 / 0.25 - (0.5 * -9.8 * 0.25)
v0 = 4 - (-1.225)
=> v0 = 5.1225 <-----------Error: =5.225


That seems valid, but now let's say I need to update the velocity 30 times per second. This means that I am starting with an initial velocity of 5.1225 m/s, and each "tick" I need to decrement the velocity by some amount. After 0.25 seconds my velocity should tick down to zero.

I am guessing I would use (v1 = v0 + a * t) per "tick" for this, correct? Where v0 is always 5.1225 and (t) increments by (1/30) in each tick?

You can use the V = Vo -a*t (treat a as negative) relationship at each 1/30 to give you V at each point leading up to 0. You can merely note in that regard that you will be decrementing by 9.8/30 = .32667m/s for each 1/30
 


>> You can merely note in that regard that you will be decrementing by 9.8/30 = .32667m/s for each 1/30

That is what I thought as well, but:

0.25 secs * 30 ticks per second = ~8 ticks
0.32667 m/s * 8 ticks = 2.61336 meters

So my velocity doesn't tick down to zero in the 0.25 seconds I have to get there.
 


goombachu said:
>> You can merely note in that regard that you will be decrementing by 9.8/30 = .32667m/s for each 1/30

That is what I thought as well, but:

0.25 secs * 30 ticks per second = ~8 ticks
0.32667 m/s * 8 ticks = 2.61336 meters

So my velocity doesn't tick down to zero in the 0.25 seconds I have to get there.

That's because you didn't calculate the maximum height. You derived an equation for what the initial velocity would be if after 1/4 sec it got to height 1 meter.

To calculate initial Velocity if the max height is 1 m then you would choose V2 = 2*(9.8)*1
That means V = 4.427m/s and the time to do that is x = 1/2*9.8*t2 and the time then is .4518 s
 
Last edited:


OK maybe I should rephrase the problem then to be clear. I need to velocity to hit zero at a predetermined height (1 meter in this example), and it needs to take exactly a predetermined amount of time (.25 seconds in this example) to get to that height. A negative force (which I thought could be gravity) must act on the projectile in order to launch it at a high speed and slow it down as it gets closer to the height.

Need to figure out:

a) What velocity to launch the projectile at in order to reach a given height at a given time
b) How to decrease the velocity in each 1/30 tick in order to reach velocity = 0 at a given time

The method you suggest looks like it doesn't get me to the predetermined height in the predetermined amount of time. At first glance it would seem that I might need to change the acceleration in order to do that?
 


goombachu said:
OK maybe I should rephrase the problem then to be clear. I need to velocity to hit zero at a predetermined height (1 meter in this example), and it needs to take exactly a predetermined amount of time (.25 seconds in this example) to get to that height. A negative force (which I thought could be gravity) must act on the projectile in order to launch it at a high speed and slow it down as it gets closer to the height.

Need to figure out:

a) What velocity to launch the projectile at in order to reach a given height at a given time
b) How to decrease the velocity in each 1/30 tick in order to reach velocity = 0 at a given time

The method you suggest looks like it doesn't get me to the predetermined height in the predetermined amount of time. At first glance it would seem that I might need to change the acceleration in order to do that?

Looks like that's all that's left that you can change then.

On a planet far, far, away there is a boy playing with a ball ...
 


Right. So now i have 2 unknowns then: initial velocity and acceleration.

I don't readily see any of the standard kinematic equations that could help me find both? The only one that doesn't involve both unknown terms is d = avg_vel * t, but that doesn't really give me an initial "launch" velocity does it?
 

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