Calculating Jump Height with Higher Gravity: Formula and Tips | Help Needed

  • Thread starter Thread starter jacksonbobby5
  • Start date Start date
Click For Summary
To calculate jump height under higher gravity, use the formula y = (-g/2)t^2 + vt, where g is the gravitational acceleration and v is the initial jump velocity. The maximum height can be determined using the formula v^2/2g. If the gravity is known, simply substitute that value for g. For unknown gravity, calculate it using g = GM/R^2, where M is the planet's mass and R is its radius. This method allows for accurate jump height calculations on different planets.
jacksonbobby5
Messages
7
Reaction score
0
I am trying to find out how far something can jump off the ground with a gravity that is greater than earth. If I have an inital velocity of the jump and the specified gravity that is pushing against the object, what formula would I use to find out how high the object can jump?

Thanks
 
Physics news on Phys.org
I hope you mean that the "specified gravity" is pulling on the object! Gravity does not "push".

You use the same formula as you would on earth. If the gravitational acceleration is g, then the formula for height is y= (-g/2)t^2+ vt where v is the initial velocity of the jump. You can find the maximum value of y, perhaps by completing the square, to be v2/2g.

If, by "a gravity that is greater than earth", you already know the acceleration due to gravity on this other planet, just use that for g. If, instead, you only know the mass and radius of the planet, you have a little more work to do.

If the planet has mass M and radius R, the acceleration due to gravity, at the surface of the planet is g= GM/R2 where G is the "universal gravitational constant".
 
So if I have a kangaroo on planet Y with a specified gravity of 12m/s^2. If he jumps with an inital velocity of 8m/s, how far would he travel?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 10 ·
Replies
10
Views
3K
Replies
5
Views
862
Replies
3
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
19
Views
2K
  • · Replies 2 ·
Replies
2
Views
8K