Calculating Kc for A+B-->C With B=0 at Equilibrium

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SUMMARY

The discussion centers on calculating the equilibrium constant (Kc) for the reaction A + B → C, specifically when the concentration of B approaches zero at equilibrium. Participants confirm that in this scenario, Kc can be simplified to Kc = [C]/[A], as the concentration of B does not contribute to the equilibrium expression. This simplification is valid because multiplying by zero yields zero, thus making the term involving B irrelevant in the calculation of Kc.

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supercalaf123
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If I'm trying to find the Kc for A + B --> C and we know that A is in excess, pushing the reaction to the right. At equilibrium, B is 0 essentially. My question is for calculating Kc = [C]/[A][ B ] do we use the equation Kc = [C]/[A] because [ B ]is essentially 0 at equilibrium?
 
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So you are saying

[tex]0 \times large~number = large~number[/tex]

Does it look like something that can be true?
 

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