Finding latent heat of ice from water cooling experiment

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Homework Statement



Hi, I've been given the following information to manipulate the results of my last physics practical:

Mass Of Water * Specific Heat Capacity of Water * Change in Temperature of Water = Latent Heat of Ice * Mass of Ice + Mass of Ice * Specific Heat Capacity of Water * Change in Temperature of Water.

Homework Equations





The Attempt at a Solution



Now, the left hand side is the energy lost by water to ice, then L(Ice)*M(Ice) is the total heat absorbed by ice but what is Mass of Ice * Specific Heat Capacity of Water * Change in Temperature of Water?
 
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When ice melts by absorbing the required latent heat of fusion from its surroundings, it transitions from ice at zero C to water at zero C. If the water bath it's melting into is not at zero C also, then both are going to change until they reach a common temperature. Hence, two different "Change of Temperature of Water"s.