Calculating Mass of a Vibrating String Using Known Quantities

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SUMMARY

The discussion focuses on calculating the mass of a vibrating string in the context of a second harmonic standing wave. Key known quantities include amplitude (A), maximum velocity (v), string length (L), and tension (T). The participants clarify that the string is fixed at both ends and derive that the maximum velocity (vy,max) is equal to Aω, allowing for the calculation of angular frequency (ω) using the ratio of vy,max to A. This enables the determination of wave speed and subsequently the mass of the string.

PREREQUISITES
  • Understanding of wave mechanics and standing waves
  • Familiarity with harmonic motion and wave equations
  • Knowledge of tension in strings and its effect on wave speed
  • Basic calculus for differentiation and solving equations
NEXT STEPS
  • Study the relationship between wave speed, tension, and mass per unit length in strings
  • Learn about the derivation of wave equations for fixed-end strings
  • Explore the concept of angular frequency (ω) and its applications in wave mechanics
  • Investigate the effects of different boundary conditions on standing waves
USEFUL FOR

Students studying physics, particularly those focusing on wave mechanics, as well as educators and anyone involved in teaching or learning about harmonic motion and string vibrations.

zengodspeed
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Homework Statement


A second harmonic standing wave has the known quantities of Amplitude (max y at antinode) A, maximum velocity (y=0 at antinode) v, string length L, tension in the string T.

Given that we know that it is second harmonic, we can assume that λ = L

How can one determine the mass of the string?

Homework Equations



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The Attempt at a Solution



Attempt at solution:

Using the equation to solve for velocity:

I know that I can find the mass of the object if I can find the wave speed, but without knowing the frequency/period of the wave I do not see how I can find this.

Thanks in advance
 

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zengodspeed said:

Homework Statement


A second harmonic standing wave has the known quantities of Amplitude (max y at antinode) A, maximum velocity (y=0 at antinode) v, string length L, tension in the string T.

Given that we know that it is second harmonic, we can assume that λ = L

How can one determine the mass of the string?

Homework Equations



View attachment 215526

View attachment 215527

View attachment 215528

The Attempt at a Solution



Attempt at solution:

Using the equation to solve for velocity:

I know that I can find the mass of the object if I can find the wave speed, but without knowing the frequency/period of the wave I do not see how I can find this.

Thanks in advance
You havn't mentioned that either string is fixed at both end or fixed at one end
because normal frequencies of standing wave depend on how end is fixed
 
Abhishek kumar said:
You havn't mentioned that either string is fixed at both end or fixed at one end
because normal frequencies of standing wave depend on how end is fixed

Hi, sorry about that. The string is fixed at both ends.
 
zengodspeed said:
the frequency/period of the wave I do not see how I can find this.
Look at your third relevant equation. What does it say about the max vy?
 
haruspex said:
Look at your third relevant equation. What does it say about the max vy?

That the max vy is equal to the derivative of the second equation when y=0?
 
zengodspeed said:
That the max vy is equal to the derivative of the second equation when y=0?
Just fix on the third equation. As t and x vary, what is the max value of the right hand side?
 
haruspex said:
Just fix on the third equation. As t and x vary, what is the max value of the right hand side?

The maximum value of the right hand side would be Aω if x and t were chosen so that sin(kx) and cos(ωt) were both equal to 1.
 
zengodspeed said:
The maximum value of the right hand side would be Aω if x and t were chosen so that sin(kx) and cos(ωt) were both equal to 1.
Right, so what is the max value of vy?
 
The max value is equal to Aω. Therefore you can solve for ω by taking the ratio of the vy,max and the amplitude.
 
  • #10
zengodspeed said:
The max value is equal to Aω. Therefore you can solve for ω by taking the ratio of the vy,max and the amplitude.
Right, and you are given vy,max.
 
  • #11
haruspex said:
Right, and you are given vy,max.

Brilliant, thank you very much!
 

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