Calculating Maximum Force Acting on 28kg Mass: F=ma

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Homework Help Overview

The problem involves calculating the maximum force acting on a mass of 28 kg, given its position as a function of time, x(t) = 3.0sin((15.0)t). The focus is on understanding the relationship between position, acceleration, and force using the equation F=ma.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to derive the acceleration from the position function by taking the second derivative, but expresses uncertainty about the correctness of their approach. They also question the choice of time variable t.

Discussion Status

Participants are actively engaging with the problem, offering hints and clarifications regarding the maximum values of the sine function and the implications for the time variable. There is a mix of interpretations regarding the approach to finding the maximum force, with no explicit consensus reached.

Contextual Notes

Some participants are questioning the assumptions related to the maximum values of the sine function and how they relate to the time variable in the context of the problem.

kopinator
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The position of a mass m = 28.0 kg is given in by x(t) = 3.0sin ((15.0)t). Calculate the magnitude of the maximum force acting on the mass.

F=ma. I tried deriving x(t) twice to get the acceleration equation so i could plug it into F=ma and then pick a random number for t. I chose t=1 but i still didn't get the right answer.
 
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Hint: the maximum value of sin(kt) or cos(kt) is 1 where k is any constant.
 
So I guessed correctly with t=1. But I'm still stumped on where to go from there. Do I still take the 2nd derivative of x(t)?
 
You are confusing the maximum value of sin(kt) with the value of t.

If k = 1, is sin (1) a a maximum? Sin (x) and Cos (x) both have maximum values of 1, but the x values where this occurs are different.
 

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