Maximum Force on a Test Mass in a Massive Ring

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SUMMARY

The discussion focuses on calculating the force exerted on a test mass m positioned along the z-axis above a massive ring with a radius of 1 and mass M. The force equations derived include F=(GMm)/r^2, leading to specific values of 0 at z=0 and 0.354 at z=1. To determine the maximum force on the test mass, participants confirm the necessity of taking the derivative of the force expression F=(2GmMx)/(x^2+a^2)^(3/2) with respect to x, setting it to zero, and solving for x.

PREREQUISITES
  • Understanding of gravitational force equations, specifically F=(GMm)/r^2
  • Knowledge of calculus, particularly differentiation and finding critical points
  • Familiarity with the concept of mass distribution in a ring
  • Basic understanding of coordinate systems in physics
NEXT STEPS
  • Study the process of taking derivatives to find maxima and minima in physics contexts
  • Explore gravitational field calculations for different mass distributions
  • Learn about the implications of symmetry in gravitational problems
  • Investigate the application of Lagrange multipliers in constrained optimization problems
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This discussion is beneficial for physics students, particularly those studying classical mechanics, as well as educators looking for examples of gravitational force calculations and optimization techniques in physics.

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Homework Statement


A massive ring (radius = a and mass = M) lies on the xy plane. Calculate the force F on a test mass m at position z on the z axis.
Now assume a = 1 and GMm/a2 = 1 in some system of units.

(a) What is the force on m at z = 0?
I got the answer for this its 0
(b) What is the force on m at z = a?
the answer for this is 0.354
(c) What is the maximum force on m ?
I am stuck on this one.


Homework Equations



F=(GMm)/r^2

The Attempt at a Solution



after some work I get F=(2GmMx)/(x^2+a^2)^3/2
i know this is right because i got part b from it, however i don't Know how to find the maximum, my gut feeling is take the derivative with respect to x and set it equal to zero and then solve for x and plug back into F
 
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kraigandrews said:
after some work I get F=(2GmMx)/(x^2+a^2)^3/2
i know this is right because i got part b from it, however i don't Know how to find the maximum, my gut feeling is take the derivative with respect to x and set it equal to zero and then solve for x and plug back into F

I'm not sure where that "2" comes from in your force expression. Better check that derivation.

And yes, you need to differentiate and solve as you've outlined.
 
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