Calculating Molal Boiling point elevation constant HELP

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SUMMARY

The discussion focuses on calculating the molal boiling point elevation constant (kb) for carbon disulfide (CS2). The normal boiling point of CS2 is 46.30°C, and when 0.250 mol of a nondissociating solute is added to 400.0 mL of CS2, the boiling point rises to 47.46°C. The calculated boiling point elevation (ΔTb) is 1.16°C, leading to a molality of 0.625 m. The final calculation for kb results in 1.856°C kg/mol.

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piggyxchu
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Calculating Molal Boiling point elevation constant! HELP!

So here's how I did my problem, but the answer I arrived with is wrong. I need help with this...:cry:

Carbon disulfide (CS2) boils at 46.30°C and has a density of 1.261g/mL.
When 0.250 mol of a nondissociating solute is dissolved in 400.0 mL of CS2, the solution boils at 47.46°C. What is the molal boiling point elevation constant for CS2?

Homework Statement


Normal Boiling Point: 46.3°C
0.250mol of solute
400.0mL of CS2 (solvent)

Homework Equations


ΔT_{b}=k_{b}(molality)

The Attempt at a Solution


ΔT_{b}=47.46-46.30=1.16°C
molality = 0.250mol/0.400kg = 0.625m

k_{b}= ΔT_{b}/molality.
k_{b}=1.16°C/0.625=1.856.
 
Last edited:
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piggyxchu said:
0.400kg

Try harder.
 


Borek said:
Try harder.
lol word

piggy, you are given the volume and the density. you want to find the mass, so what do you do?
 

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