Calculating Normal Force in a Bridge: Truck at x=29m - Step by Step Guide

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SUMMARY

The discussion focuses on calculating the normal force at each support of a bridge with a length of 72 meters and a mass of 64,000 kg, when a truck weighing 20,000 kg is positioned at 29 meters from the left support. The key equation used is T=F x sinx, which relates to the forces acting on the bridge. It is established that the normal force acts as a reactive vertical force at the supports, and the solution involves ensuring the sum of torques equals zero to determine the forces accurately.

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1. Homework Statement [
A bridge of length L=72 m and mass 64000 kg is supported at each end. A truck of mass 20000kg is located at x=29m from the left support. Calculate the normal force at each support.

Homework Equations


T=F x sinx


The Attempt at a Solution


Is the normal force the same as the tension?
 
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I'd assume the 'normal' force at the support is the 'vertical' force, i.e. the statistical force acting as a reactive force at the support.
 
think of each support as different possible origins of your system. Then figure out the upward force necessary to keep the sum of torques equal to zero.
 

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