Calculating Odds of Coin Toss: Accurate?

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The probability of a coin toss resulting in heads is indeed 1 in 2. For multiple consecutive heads, the probability is calculated as 1 in 2 raised to the power of the number of tosses, meaning for two heads it is 1 in 4, for three heads it is 1 in 8, and so forth. This can be verified by listing all possible outcomes and counting the favorable ones. The formula for n tosses is 1/2^n, confirming the calculations. Understanding these probabilities is essential for accurate predictions in coin toss scenarios.
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the chance of a coin toss coming up heads is 1 in 2. i assume that the chance of it coming up heads twice in a row is 1 in 4; three times consecutively 1 in 8; 4 times 1 in 16; 5 times 1 in 32, etc... is this accurate? if not, how would that be calculated?

tyia
 
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That's right. For the first few cases you can write down the outcomes. Such as H T, HH HT TH TT, and so on, count the number of events favourable to the outcome of all tosses showing a head(which is 1 in all cases), and count the total number of outcomes. You will notice that for n tosses, the probability is \frac{1}{2^n}.
 
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Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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