Calculating Odds of Coin Toss: Accurate?

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SUMMARY

The probability of a coin toss resulting in heads is accurately defined as 1 in 2. For multiple consecutive tosses, the probability of obtaining heads n times in a row is calculated as 1 in 2 raised to the power of n, or 1 in 2n. For example, the probability of getting heads twice is 1 in 4, three times is 1 in 8, and so forth. This calculation is confirmed by analyzing the total number of outcomes versus the favorable outcomes for heads.

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the chance of a coin toss coming up heads is 1 in 2. i assume that the chance of it coming up heads twice in a row is 1 in 4; three times consecutively 1 in 8; 4 times 1 in 16; 5 times 1 in 32, etc... is this accurate? if not, how would that be calculated?

tyia
 
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That's right. For the first few cases you can write down the outcomes. Such as H T, HH HT TH TT, and so on, count the number of events favourable to the outcome of all tosses showing a head(which is 1 in all cases), and count the total number of outcomes. You will notice that for n tosses, the probability is [itex]\frac{1}{2^n}[/itex].
 
thanks
 

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