Calculating Orbital Radius of Ganymede using Orbital Period

Click For Summary

Homework Help Overview

The discussion revolves around calculating the orbital radius of Ganymede, one of Jupiter's moons, based on its orbital period of 7.15 days. Participants reference a related example problem involving the orbital periods and distances of other moons of Jupiter, specifically Io and Callisto, to establish a method for their calculations.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of Kepler's third law of planetary motion to relate the periods and distances of celestial bodies. There are attempts to manipulate the given formula to find the orbital radius for Ganymede, with some questioning the correctness of the textbook's provided answer.

Discussion Status

The conversation is ongoing, with participants sharing their calculations and questioning the assumptions made in the problem. Some express uncertainty about the textbook's answer, while others suggest verifying the algebraic manipulations before using a calculator to minimize errors.

Contextual Notes

Participants note discrepancies between their calculated results and the textbook's answer, leading to discussions about the implications of the relationships between orbital period and radius. There is an emphasis on ensuring accurate reading of the problem statement and the relationships defined within it.

trekkie1701c
Messages
7
Reaction score
0

Homework Statement


"If Ganymede, one of Jupiter's moons, has a pariod of 7.15 days, how many uits are there in it's orbital radius? Use the information given in Example Problem 1."

Example Problem:

"Galileo measured the orbital sizes of Jupiter's moons using the diameter of Jupiter as a unit of measure. He found that Io, the closest moon to Jupiter, had a period of 1.8 days and was 4.2 units from the center of Jupiter. Callisto, the fourth moon from Jupiter, had a period of 16.7 days. Using the same units that Galileo used, predict Callisto's distance from Jupiter."


Homework Equations



(Ta/Tb)^2=(Ra/Rb)^3

The Attempt at a Solution



My solution to the example problem:

Ta = 1.8
Tb = 16.7
Ra = 4.2

(1.8/16.7)^2 = (4.2/Rb)^3

.0116 = 74.088(Rb^3) (Dividing 1.8 by 16.2 and squaring, and cubing 4.2 and Rb)
.2264Rb=4.2 (Multiplying by Rb^3 and then taking the cubed root of everything)
Rb=18.5512 (Dividing by .2264)

I considered that since the book gave an answer of 19, that I was close enough, considering the book's want to round everything.

For the problem I'm having difficulty with, I did this:

Ta = 1.8
Tb = 7.15
Ra = 4.2

(1.8/7.15)^2 = (4.2/Rb)^3
.2517^2=4.2^3/Rb^3 (1.8 divided by 7.15)
.0634=4.2^3/Rb^3 (Squaring previous answer)
.0634(Rb^3)=4.2^3 (Multiplying by Rb^3)
.3987Rb=4.2 (Taking the cubed root of both sides)
Rb=10.5342 (Dividing by .3987)

The book, however, lists an answer of exactly 4. I can't figure out where I messed up.
 
Physics news on Phys.org
Well, if Tb > Ta then Rb > Ra. In other words, the text must have the wrong answer. (My result is the same as yours).

Next time, try to do all of the algebric manipulations before punching the numbers into the calculator. There are a couple of good reasons for doing this: you are less likely to make an error with the calculator, mistakes are a lot easier to track down and it makes it easier for the marker/fellow students to follow your steps (symbols are easier to follow than numbers).

Hope it helps.
 
Are you sure you are reading the problem correctly? A body with an orbital radius of 4 units would obviously have a shorter period than a body with a radius of 4.2 units.
 
I read it correctly. The problems I listed above are word for word what's in the textbook.

And, link2001. Thanks; I'll start doing that from now on.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
7K
  • · Replies 1 ·
Replies
1
Views
4K
Replies
12
Views
5K
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
8K
Replies
6
Views
3K
Replies
9
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
10
Views
3K