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Calculating orbital speed/period

  • Thread starter ARJewell
  • Start date
6
0
1. Homework Statement
The mass of the sun is 2x10^30kg and the planet Jupiter averages an orbital distanceof 5.2 AU. Calculate the orbital speed (in mph) and orbital period (in earth years) of Jupiter relative to the Sun: One AU is one Astronomical Unit which is the average earth-sun distance... 1 AU = 1.5x10^11m.

2. Homework Equations

Vorb= sqrt(GM/r)

T=(2pi*r)/sqrt(GM/r)

r = (1.5x10^11m)(5.2) = 7.8x10^11m
G = 6.67x10^-11 Nm^2/kg^2
M= 2x10^20kg

3. The Attempt at a Solution

I plugged in the numbers and ended up with...

Vorb = 4.39 x 10^4 m/s = 98199.91 mph
T= 374751912s = 11.88 years

Does this look right?
 

Answers and Replies

kuruman
Science Advisor
Homework Helper
Insights Author
Gold Member
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Why don't you look up the orbital period of Jupiter and see for yourself?
 

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