Calculating orbital speed/period

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SUMMARY

The orbital speed of Jupiter relative to the Sun is calculated to be approximately 98,199.91 mph, while its orbital period is determined to be about 11.88 Earth years. These calculations utilize the gravitational constant (G = 6.67 x 10^-11 Nm^2/kg^2) and the mass of the Sun (M = 2 x 10^30 kg). The average orbital distance of Jupiter is 5.2 AU, which translates to 7.8 x 10^11 meters. The formulas used for these calculations are Vorb = sqrt(GM/r) for speed and T = (2πr)/sqrt(GM/r) for the period.

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Homework Statement


The mass of the sun is 2x10^30kg and the planet Jupiter averages an orbital distanceof 5.2 AU. Calculate the orbital speed (in mph) and orbital period (in Earth years) of Jupiter relative to the Sun: One AU is one Astronomical Unit which is the average earth-sun distance... 1 AU = 1.5x10^11m.

Homework Equations



Vorb= sqrt(GM/r)

T=(2pi*r)/sqrt(GM/r)

r = (1.5x10^11m)(5.2) = 7.8x10^11m
G = 6.67x10^-11 Nm^2/kg^2
M= 2x10^20kg

The Attempt at a Solution



I plugged in the numbers and ended up with...

Vorb = 4.39 x 10^4 m/s = 98199.91 mph
T= 374751912s = 11.88 years

Does this look right?
 
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