Calculating pH of a Monoacidic Base Solution in Water

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Discussion Overview

The discussion revolves around calculating the pH of a solution of a strong monoacidic base dissolved in water. Participants explore the relationship between pH, pOH, and the concentration of hydroxide ions generated by the base.

Discussion Character

  • Homework-related
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant suggests that the pH of the solution could be calculated using the formula (a) -log x, (b) 14-log x, (c) 14+log x, or (d) -log (14-x), but expresses confusion about how to start the calculation.
  • Another participant clarifies the term "monoacidic base," indicating it refers to a base that generates one mole of OH- per mole of base in water, and mentions relevant equations for pH and the water ion product.
  • A different participant proposes calculating pOH first as -log[OH-], then deriving pH from pH = 14 - pOH.
  • One participant emphasizes that it is not explicitly stated that the base generates one mole of OH-, prompting further clarification on the definition of a monoacidic base.
  • Another participant notes that monoacidic bases can be represented as MOH, where M is a univalent metal, and suggests using the mole concept to relate the concentration of the base to the hydroxide ions produced.
  • There is a brief mention of Gay Lussac's law and Avogadro's law, which one participant questions as being relevant to the pH calculation.
  • A participant expresses satisfaction with the problem-solving process, stating they found pOH and subsequently calculated pH easily, while also addressing a previous comment about their understanding of the mole concept.
  • Lastly, a participant notes the importance of the water ion product, pH, and pOH for future reference.

Areas of Agreement / Disagreement

Participants express varying levels of understanding regarding the definition of a monoacidic base and its implications for calculating pH. There is no consensus on the exact approach to take, and multiple viewpoints on the definitions and calculations remain present.

Contextual Notes

Some participants highlight the need for clarity on the assumptions regarding the generation of hydroxide ions from the monoacidic base, as well as the relevance of certain gas laws to the discussion.

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Homework Statement


x mole of a strong monoacidic base is dissolved in one litre of water. The pH of the solution will be
(a)-log x
(b)14-log x
(c)14+log x
(d)-log (14-x)


Homework Equations





The Attempt at a Solution



For instance i assumed that the base is NaOH but it does not react with water to form any compound. So i am confused how should i start?

Thanks! :smile:
 
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I'm still working on "monoacidic base"...
What's that?

OK. I just Googled it. So you have a base that generates 1 mole of OH- per mole of base in water. You also know the following:
1) pH = -log[H+]
2) [H+][OH-] = 1.01 X 10-14

Can you get it from there?
 
Last edited:
First calculate the pOH, which equals to -log[OH-].
Then, pH=14-pOH. That's it.
 
chemisttree said:
I'm still working on "monoacidic base"...
What's that?

OK. I just Googled it. So you have a base that generates 1 mole of OH- per mole of base in water. You also know the following:
1) pH = -log[H+]
2) [H+][OH-] = 1.01 X 10-14

Can you get it from there?

I think it isn't stated that it generates one mole of OH-. :smile:
 
Pranav-Arora said:
I think it isn't stated that it generates one mole of OH-. :smile:

Monoacidic base is written in the form of MOH where M is any univalent metal.

Hints :
1 mole of MOH in water furnishes one OH- ion.
Then x moles of MOH will furnish... ?

Write an ionic equation in terms of "x" and think about Mole Concept once again. You can then use the formulas given by chemisttree.
 
Last edited:
sankalpmittal said:
think about Gay Lussac's law and Avogadro's law.

Huh? What do the laws concerning gases have to do with the pH of the solution?
 
This isn't a hard question as i thought of and thanks to chemistree for the idea of pOH.

I found out the pOH which is -log x. Then calculated pH, which is completely easy pH=14-pH.

@sankalp:- I think i am not that bad at chemistry that you need to remind me of Mole concept.

I just forgot to reply in this thread after solving the problem. :P
 

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