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coookiemonste
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Homework Statement
Find the pH of water in limestone (CaCO3) quarry.
H2CO3 pk1=6.37, pk2=10.32
Homework Equations
pH=pKa + log [conjugate base]/[acid]
Kw=10^-14
The Attempt at a Solution
CO3 2- + H2O -> HCO3- + OH-
Ka= [HCO3-][OH-]/[CO3 2-]
10^-10.32=x^2/[10^-6.37]
[OH-]=x=.01059
-log[OH-]=1.98
14-1.98=12.02
is this correct?
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