Calculating Poisson ratio is a way to measure a material's response to stress.

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    Poisson Ratio
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Homework Help Overview

The discussion revolves around calculating the Poisson ratio of a cylindrical metal specimen under tensile stress. The original poster presents a problem involving a specific force applied to the specimen and the resulting change in diameter, along with the elastic modulus of the material.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the original poster's method for calculating the Poisson ratio, questioning the accuracy of their calculations and the validity of the equations used. There is also exploration of alternative formulations of the equations.

Discussion Status

The conversation is ongoing, with participants providing feedback on the original poster's calculations and suggesting potential sources of error. There is no explicit consensus on the correct answer, as different values for the Poisson ratio have been reported by participants.

Contextual Notes

Participants are working with specific values for force, diameter, and elastic modulus, and there is mention of a tutorial sheet providing a different answer, which adds to the confusion regarding the calculations.

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Homework Statement


question

A ciclindrical metal specimen 10 mm in diameter is stressed elastically in tension. A force of 15000 N produces a reduction in diameter of 0.007 mm. Compute Poisson ratio if its elastic modulus is 100 GPa



Homework Equations



E=stress/strain




The Attempt at a Solution



my attempt

D original = 0.01m
change in D = 0.000007m
F=15000N
E= 100*10^9

V = passonse ratio = (change in D/D original)/(change in L/ L original)

we can replace (change in L/ L original) by (stress/E)

so

V=(change in D/D original)/(stress/E)

(change in D/D original) = (0.000007/0.01)
(stress/E) = (F/Area)/E
A= pi(0.01/2)^2

that gives me an answer of V = 0.21



but the tutorial sheet says the answer is 0.33

can you explain where i have gone wrong
 
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Your method looks fine to me, though I got ν=0.27.
 
vela said:
Your method looks fine to me, though I got ν=0.27.



elongation D = (4*F*V)/(pi*Doriginal*E)

is this a valid eqation??
 
buxZED said:
elongation D = (4*F*V)/(pi*Doriginal*E)

is this a valid eqation??
That might look more familiar if you divide both sides by D and rearrange it slightly:

\frac{\Delta D}{D} = \frac{4 F \nu}{\pi D^2 E} = \frac{F}{\pi(D/2)^2 E}\nu = \frac{F}{AE}\nu

where A = \pi(D/2)^2 is the cross-sectional area.
 
vela said:
That might look more familiar if you divide both sides by D and rearrange it slightly:

\frac{\Delta D}{D} = \frac{4 F \nu}{\pi D^2 E} = \frac{F}{\pi(D/2)^2 E}\nu = \frac{F}{AE}\nu

where A = \pi(D/2)^2 is the cross-sectional area.
why dose using this equation gives me a different answer for passoinse ratio?
 
It shouldn't. I suspect you're just making other errors while calculating or rounding off too much on intermediate steps. After all, I did the exact same calculations you did in your original post and got 0.27 while you got 0.21.
 
vela said:
It shouldn't. I suspect you're just making other errors while calculating or rounding off too much on intermediate steps. After all, I did the exact same calculations you did in your original post and got 0.27 while you got 0.21.

i don't get it an I am confused
can u do a quick run true and tell me they are same?
 

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