Calculating Population Growth: 1 & 5 Yrs Ago

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Homework Help Overview

The discussion revolves around calculating past population figures based on a steady annual growth rate of 2.7% over the last five years, with the current population given as 15.2 million. Participants are exploring how to derive the population figures for one and five years ago.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the formula for compound growth, with one suggesting a rearrangement of the compound interest formula to find past population values. There is also a clarification on the interpretation of the time variable in the context of the problem.

Discussion Status

The discussion includes various attempts to clarify the formula and its application. Some participants offer hints and guidance on how to approach the calculations, while others express uncertainty about the correct interpretation of the problem.

Contextual Notes

There is a mention of the need to remember specific formulas and the implications of the growth rate over the specified time periods. The original poster indicates a lack of confidence in recalling the necessary formula.

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I am not too sure what to do to answer this question.
Each year for the past 5 years the population of a certain country has increased by a steady rate of 2.7% per annum. The present population is 15.2 million.
a) what was thepopulation 1 yr ago?
b) what was the population 5 years ago?

I forgot what formula to use. Any help and reminders welcome. Thanks
 
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Well, then re-develop that formula using your head (and our hints).
You start out!:smile:
 
I know the normal formula for compound interest is
un = u1 * r^(n-1)
so rearranging that would give u1 = ___(1.027)^5_____
15.2 * 10^6
 
then multiply that answer by (1.027)^(5-1)
 
Not sure what you are doing here. "1 year ago from n=1" is n-value n=0.
Plug that into your equation.
 
thanks I have already worked this out, sorry
 

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