Calculating Potential Energy in a Rotary Mousetrap Spring System

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Homework Help Overview

The discussion revolves around calculating the potential energy of a spring in a rotary mousetrap system, specifically as a function of the angle the spring is pulled back. The subject area includes concepts from mechanics and spring dynamics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between angle and potential energy, with one suggesting the use of a linear approximation for the spring. Questions arise regarding the nature of the spring (linear vs. torsion) and the appropriate equations to use.

Discussion Status

The discussion is active, with participants providing insights and questioning the assumptions about the spring's behavior. Some guidance has been offered regarding the equations, but multiple interpretations of the spring's characteristics are being explored.

Contextual Notes

There is uncertainty about whether the spring behaves linearly and how to determine the spring constant. The need for a diagram to clarify the system setup has also been mentioned.

JLT
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Homework Statement



Calculate the potential energy created by the spring in the mousetrap as a function of the angle the spring is pulled back.

Homework Equations



PE = ∫Fdx = ∫ kxdx = ∫k rΘ rdΘ ??

The Attempt at a Solution



Is this a linear spring? we can use x = rΘ, and dx = rdΘ, so PE = ½k(rΘ)^2

↑↑ does that look good to everyone, or is there a better soln to this?
 
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Is this an experiment? What measurements could you take to help determine if it is linear and to determine k?
 
JLT said:
the spring in the mousetrap
Is there a diagram with this?
It sounds like a so-called torsion spring. Mousetraps generally use those.
 
OK, although for a rotary system the spring constant is usually given as τ = kθ, τ = torque, then
p.e. = 1/2 kθ2.
 

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