Calculating Potential Energy of 4 Charges - Deriving V(x,y,z)

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SUMMARY

The discussion centers on calculating the potential energy of four equal charges, each of magnitude q, positioned at coordinates r1 = (+1, +1, 0), r2 = (-1, +1, 0), r3 = (-1, -1, 0), and r4 = (+1, -1, 0). The goal is to derive the potential energy function V(x, y, z) near the origin, expressed as V(x, y, z) = V0 + Ax² + By² + Cz². Participants emphasize the importance of expanding V using a Taylor series around the origin, noting that the first-order terms vanish, which is crucial for understanding the stability of the equilibrium configuration against small displacements.

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  • Understanding of electrostatics and Coulomb's law
  • Familiarity with Taylor series expansions in multivariable calculus
  • Knowledge of electric fields and potential energy concepts
  • Basic principles of stability analysis in physics
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kuahji
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Consider 4 charges all of magnitude q located at the following positions:
r1 = (+1; +1; 0) ; r2 = (-1; +1; 0) ; r3 = (-1;-1; 0) ; r4 = (+1;-1; 0)

We now want to study the stability of such an equilibrium con guration against
small displacements. Show that near the origin the potential energy felt by the test particle may be written as
V (x; y; z) = V0 + Ax^2 + By^2 + Cz^2 + ...

Where a test charge e is at the origin.

I'm a bit confused about how to arrive at this derivation. In general we have E=-\nablaV, so if we have the electric field at the origin, we can get the potential. However it does not turn out to be the above. Any help on getting me started?
 
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Expand V as a Taylor series about the origin. You should find the first-order terms vanish.
 

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