Calculating Power and Resistance of a Domestic Bulb with 0.25A and 12V

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Homework Help Overview

The discussion revolves around calculating the power and resistance of a domestic bulb given a current of 0.25A and a voltage of 12V. The subject area pertains to basic electrical principles, specifically Ohm's Law and power calculations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of power using the formula for power (P = IV) and express uncertainty about calculating resistance. There are inquiries about the application of Ohm's Law and whether the original poster is applying the concepts correctly.

Discussion Status

Some participants have provided guidance on the relationship between current, voltage, and power, while others have prompted the original poster to share their attempts and clarify their understanding of relevant laws. The discussion is ongoing, with various interpretations and levels of understanding being explored.

Contextual Notes

The original poster indicates they are new to physics and seeking assistance, which may imply a lack of familiarity with foundational concepts. There is also a mention of being in their first year of study, suggesting potential constraints in their background knowledge.

hgo0
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A current of 0.25A flows through a bulb when a voltage of 12V is applied across it. Calculate the power and resistance of the bulb.

please show working out
 
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Welcome to PF!

Hi hgo0! Welcome to PF! :wink:

Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 
0.25A x 12V = 3W

i don't know how to get the resistance or if I am doing this right :rolleyes:
 
hgo0 said:
0.25A x 12V = 3W

Hi hgo0! :smile:

That's right: amps times volts = watts (or current times voltage = power).
i don't know how to get the resistance or if I am doing this right :rolleyes:

Have you done Ohm's Law (or Kirchhoff's rules ) ? If not, look them up.

V = IR (or potential difference = voltage = current times resistance). :wink:
 
kk thanks a lot I'm new to physics (first year) and failing soo i need all the help i can get :biggrin:
 

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