The discussion revolves around calculating the power required for the evaporation of water, given its heat of vaporization of 2260 kJ/kg and an evaporation rate of 0.25 g/s. Participants are exploring the relationship between energy, mass, and power in this context.
Some participants have provided equations and initial calculations, while others have pointed out the need for unit conversions. There is an ongoing exploration of the calculations without a definitive consensus on the final approach.
There is a noted need to convert the heat of vaporization from kJ to joules to align with SI units, which is under discussion. The original poster has not yet provided a complete solution or final answer.
adjacent said:You can use ##E=mL_v## and ##P= \frac{E}{t}##
Please show your progress
It looks correct.Bgerst103 said: