MHB Calculating Probability for Non-consecutive Lockers in a Discrete Model

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The discussion focuses on calculating the probability that three individuals randomly choose lockers from a set of 12 consecutive lockers without selecting consecutive ones. The original solution provided by the teacher is confusing, particularly regarding the numbers used in the calculations. A clearer approach involves modeling the problem with a binary string representation, where '1's indicate chosen lockers and '0's represent empty lockers. By arranging the string to ensure no two '1's are adjacent, the solution can be derived from the available spaces created by the '0's. Understanding this model clarifies the probability calculation for non-consecutive selections.
Abstract3000
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Hello,
I have a question I am trying to figure out how it works and I am so confused I need a break down of what is exactly going on with this problem

the Question.
"Concern three persons who each randomly choose a locker among 12 consecutive lockers"

What is the probability that no two lockers are consecutive?

The answer given that confuses me even more:
-----------------------------------------------------------------------
1st to find ways exactly 2 lockers are consecutive

X X _ _ _ _ _ _ _ _ _ _ 9 Ways
_ X X _ _ _ _ _ _ _ _ _ 8 Ways
_ _ X X _ _ _ _ _ _ _ _ 8 Ways

5 others w/8

_ _ _ _ _ _ _ _ X X _ _ 8
_ _ _ _ _ _ _ _ _ X X _ 8
_ _ _ _ _ _ _ _ _ _ X X 9

# = 9X2 + 9X8 = 90
Next # Ways w/3 consecutive = 10 start in 1,2,...,10

== P(no 2 consec) = 1 - 100/C(12,3) ~ .545 = 5.45X10^10-1
--------------------------------------------------------------------------

This is the teachers solution and I have absolutely no idea on how he got all the number he did I am really lost (on all of it, the solution makes no sense in what he has written down I don't get where he gets the 8's the 9's or the 10 from), anyone understand this and have the time to break it down for me?

Thanks!
 
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Re: Discrete Probability Quetion

Abstract3000 said:
"Concern three persons who each randomly choose a locker among 12 consecutive lockers"
What is the probability that no two lockers are consecutive?

This is the teachers solution and I have absolutely no idea on how he got all the number he did I am really lost (on all of it, the solution makes no sense in what he has written down I don't get where he gets the 8's the 9's or the 10 from), anyone understand this and have the time to break it down for me?

I do not follow that solution either. But here is a model.
Think of a string 111000000000, the 1's represent the chosen lockers and the 0's empty.
100100000100 in that model no two chosen lockers are consecutive.
But in 001000001100 in that model two chosen lockers are consecutive.

So how many ways can we rearrange the string 111000000000 so no two 1's are consecutive?

\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_ Note that the nine 0's create ten places that we can place the 1's so no two are consecutive.

Here is the caculation.
 
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First trick I learned this one a long time ago and have used it to entertain and amuse young kids. Ask your friend to write down a three-digit number without showing it to you. Then ask him or her to rearrange the digits to form a new three-digit number. After that, write whichever is the larger number above the other number, and then subtract the smaller from the larger, making sure that you don't see any of the numbers. Then ask the young "victim" to tell you any two of the digits of the...

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