MHB Calculating Probability for Non-consecutive Lockers in a Discrete Model

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The discussion focuses on calculating the probability that three individuals randomly choose lockers from a set of 12 consecutive lockers without selecting consecutive ones. The original solution provided by the teacher is confusing, particularly regarding the numbers used in the calculations. A clearer approach involves modeling the problem with a binary string representation, where '1's indicate chosen lockers and '0's represent empty lockers. By arranging the string to ensure no two '1's are adjacent, the solution can be derived from the available spaces created by the '0's. Understanding this model clarifies the probability calculation for non-consecutive selections.
Abstract3000
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Hello,
I have a question I am trying to figure out how it works and I am so confused I need a break down of what is exactly going on with this problem

the Question.
"Concern three persons who each randomly choose a locker among 12 consecutive lockers"

What is the probability that no two lockers are consecutive?

The answer given that confuses me even more:
-----------------------------------------------------------------------
1st to find ways exactly 2 lockers are consecutive

X X _ _ _ _ _ _ _ _ _ _ 9 Ways
_ X X _ _ _ _ _ _ _ _ _ 8 Ways
_ _ X X _ _ _ _ _ _ _ _ 8 Ways

5 others w/8

_ _ _ _ _ _ _ _ X X _ _ 8
_ _ _ _ _ _ _ _ _ X X _ 8
_ _ _ _ _ _ _ _ _ _ X X 9

# = 9X2 + 9X8 = 90
Next # Ways w/3 consecutive = 10 start in 1,2,...,10

== P(no 2 consec) = 1 - 100/C(12,3) ~ .545 = 5.45X10^10-1
--------------------------------------------------------------------------

This is the teachers solution and I have absolutely no idea on how he got all the number he did I am really lost (on all of it, the solution makes no sense in what he has written down I don't get where he gets the 8's the 9's or the 10 from), anyone understand this and have the time to break it down for me?

Thanks!
 
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Re: Discrete Probability Quetion

Abstract3000 said:
"Concern three persons who each randomly choose a locker among 12 consecutive lockers"
What is the probability that no two lockers are consecutive?

This is the teachers solution and I have absolutely no idea on how he got all the number he did I am really lost (on all of it, the solution makes no sense in what he has written down I don't get where he gets the 8's the 9's or the 10 from), anyone understand this and have the time to break it down for me?

I do not follow that solution either. But here is a model.
Think of a string 111000000000, the 1's represent the chosen lockers and the 0's empty.
100100000100 in that model no two chosen lockers are consecutive.
But in 001000001100 in that model two chosen lockers are consecutive.

So how many ways can we rearrange the string 111000000000 so no two 1's are consecutive?

\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_0\_\_ Note that the nine 0's create ten places that we can place the 1's so no two are consecutive.

Here is the caculation.
 
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There is a nice little variation of the problem. The host says, after you have chosen the door, that you can change your guess, but to sweeten the deal, he says you can choose the two other doors, if you wish. This proposition is a no brainer, however before you are quick enough to accept it, the host opens one of the two doors and it is empty. In this version you really want to change your pick, but at the same time ask yourself is the host impartial and does that change anything. The host...

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