Calculating Relative Speed & Time to Meet: I Can't Find the Distance

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SUMMARY

The discussion focuses on calculating the distance covered by two individuals, A and B, moving towards each other on a circular track with a circumference of 100 meters. A's speed is 3 m/s and B's speed is 1 m/s, resulting in a relative speed of 4 m/s. The time taken for them to meet for the first time is determined to be 25 seconds, leading to the conclusion that A covers 75 meters and B covers 25 meters before they meet.

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  • Understanding of relative speed calculations
  • Basic knowledge of distance, speed, and time relationships
  • Familiarity with linear equations
  • Concept of circular track circumference
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  • Learn how to apply the formula for distance = speed × time
  • Explore circular motion and its implications in real-world scenarios
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This discussion is beneficial for students studying physics, educators teaching motion concepts, and anyone interested in solving problems related to relative speed and distance calculations.

Benjamin_harsh
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Homework Statement
What is the Distance in Meeting for first time for opposite direction?
Relevant Equations
relative speed of A and B = 3 + 1; 4m/sec

Time for meeting for first time in opposite direction = 100/(3+1); 25 sec
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I able to calculate this 2 things:

relative speed of A and B = 3 + 1; 4m/sec

Time for meeting for first time in opposite direction = 100/(3+1); 25 sec

I can't able to find distance in Meeting for first time for opposite direction.
 
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Benjamin_harsh said:
I can't able to find distance in Meeting for first time for opposite direction.
You have the time and the velocity, so you should be able to recover a distance.
 
you say "relative speed of A and B= 3+ 1; 4 m/s". I assume you mean that A's speed is 3 m/s and B's speed is 1 m/s although you don't actually say that. In time t seconds, A, running at 3 m/s will cover 3t m. Similarly B, running at 1 m/s, will cover t m. When they meet that total distance will be the circumference of the circular track, which, I presume, is 100 m (again, you don't actually say that) so we want to have 3t+ t= 4t= 100 so t= 25 s.

Now, what distance will A, running at 3 m/s, cover in 25 seconds. What distance will B, running at 1 m/s cover in 25 seconds?
 

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