How Do Response Factors for Na and K Compare Using Li as an Internal Standard?

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The discussion focuses on calculating the response factors for sodium (Na) and potassium (K) using lithium (Li) as an internal standard. The concentration and signal ratios provided indicate that Na has a response factor of 13.5, while K has a response factor of 17.7. The calculations utilize the equation Ax/x = F(As/s), where Ax is the absorption signal of the analyte and As is the absorption signal of the standard. The poster expresses uncertainty about the simplicity of the problem and seeks validation of their results. The context suggests that the calculations relate to principles of chromatography and spectroscopy.
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Homework Statement



Determine the response factors for both Na and K with the Li internal standard

Concentration Ratio
Na : K : Li (in ppm)
5.0 : 5.0: 500
-------------------

Signal Ratio
Na : K : Li (relative units)
4.9 : 6.4: 36.2

Homework Equations



Ax/x = F(As/s)
Ax = Absorbtion signal of analyte
x = concentration of analyte
F = response factor
As = absorbtion signal of standard
s = concentration of standard

The Attempt at a Solution



Calculation for Na

(4.9)/(5.0) = F [(36.2)/(500)]
F = 13.5

Calculation for K

(6.4)/(5.0) = F [(36.2)/(500)]
F = 17.7

Seems simple enough right? So I was hoping that someone would be able to tell me if this is correct or incorrect because I have a funny feeling I did something strange (problem was too easy).
 
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It would be helpful to have more information on the equation and the reference, but based on the limited information provided, Ax/x = F(As/s), it would appear that the answers given are correct.

Is the problem/question based on an example of chromatography and spectroscopy?