Calculating RH and Heated Air Take-Up

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SUMMARY

The discussion focuses on calculating the water take-up in heated air using a fan delivering air at 1000 cu m/hr from an ambient source with specific temperature and humidity conditions. The initial parameters include a dry bulb temperature of 27°C and a wet bulb temperature of 24.3°C, resulting in approximately 80% relative humidity (RH). After heating the air to 65°C and achieving 100% RH, the confirmed water take-up is 189.6 Kg/hr, considering the expansion of air to 1126.7 cu m/hr.

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chrislock
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I know that this is a bit off the beaten track, (its a physics question) but I'm trying to confirm the results of a piece of software I've written.

If you have a fan delivering air at 1000 cu m/hr from an ambient source at 27C Dry bulb and 24.3C wetbulb (approx 80%RH i.e. 18 gmswater/ Kg air) and you heat and then spray the resultant air with water to ensure its at 65C and 100% RH - what is the take up of water into the air, assuming it all gets removed? i.e. how many KG / hr.

This sounds complicated but it really isnt. I just need someone to confirm my answer.
Thanks,
Chris
 
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I didnt really want to give this - in case it influenced anyone else's!
(I will if you have an answer though)
Vhris
 
Sorry, but that's not how it works here. We don't just hand out answers, we help people find them. So as a starting point, we need what you have so far.
 
OK - 1365.3 Kg/hr, taking into account the expansion of air (8112 cu m/hr)
Chris
 
Sorry - I entered the wrong info!
189.6 Kg/hr, taking into account the expansion of air (1126.7 cu m/hr)
Chris
 

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