Calculating Rotational Forces: Understanding Motor Dynamics | Diagram Included

  • Thread starter Thread starter Brian23
  • Start date Start date
  • Tags Tags
    Forces
Click For Summary
SUMMARY

This discussion focuses on calculating rotational forces in motor dynamics, specifically using the formula F = T/R, where F is the force, T is the torque, and R is the radius from the motor shaft. The example provided illustrates that with a motor torque of 10Nm, the force at point A (0.1m from the center) is 100N, while the force at point B (0.5m from the center) is 20N. The diagram accompanying the discussion clarifies the relationship between the motor, shaft, and attached beam.

PREREQUISITES
  • Understanding of torque in mechanical systems
  • Familiarity with rotational dynamics
  • Basic knowledge of force calculations
  • Ability to interpret mechanical diagrams
NEXT STEPS
  • Study the principles of torque and its applications in motors
  • Learn about the relationship between torque, force, and radius in mechanical systems
  • Explore advanced topics in rotational dynamics, including angular momentum
  • Investigate the effects of varying radius on force calculations in different mechanical setups
USEFUL FOR

Engineers, mechanical designers, and students studying motor dynamics and rotational mechanics will benefit from this discussion.

Brian23
Messages
2
Reaction score
0
1.jpg


Please have a look at the diagram. The black circle represents a motor, the green circle represents the rotating shaft of the motor, and the red beam is attached to the motor's shaft. The motor spins the red beam counter clockwise in the direction of the arrows.

What I need to know is how to calculate the rotational force at point A, and at point B. Thanks.
 
Last edited:
Engineering news on Phys.org
If the motor produces a torque T then the force at any point along the arm is given by F = T/R where R is the radius (eg the distance from the centre of the motor shaft to the point).

So if the motor Torque was 10Nm and Point A was 0.1m from the centre then the force at A would be 10/0.1 = 100N. If point B is at 0.2m then the force at B would be 10/0.5 = 50N.
 
  • Like
Likes Brian23
Thanks a lot for your help.
 

Similar threads

Replies
9
Views
2K
Replies
3
Views
5K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 17 ·
Replies
17
Views
4K
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
4
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K