Calculating Rotational Inertia of a Rectangular Prism

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
4 replies · 3K views
r16
Messages
42
Reaction score
0

Homework Statement


There is a rectangular prism of uniform mass distribution with lengths of [itex]a[/itex], [itex]b[/itex], and [itex]c[/itex] (b>a>c). Calculate it's rotational inertia about an axis through one corner and perpendicular to the large faces.

Homework Equations


[tex]I = \int r^2 dm[/tex]
[tex]r^2 = x^2 + y^2 + z^2[/tex]
[tex]\rho = \frac{M}{V}[/tex]
[tex]V = abc[/tex]

The Attempt at a Solution



I am examining a cubic differential mass of [itex]dm[/itex]'s contribution on the moment of inertia about the axis of rotation. The radius between [itex]dm[/itex] and the axis of rotation is [itex]r^2 = x^2 + y^2 + z^2[/itex]. The density, [itex]\rho[/itex], is constant which is [itex]\frac{M}{V}[/itex], so [itex]dm = \rho dV[/itex].

[tex]I = \int r^2 dm = \int (x^2 + y^2 + z^2) \rho dV[/tex]
[tex]I = \rho \iiint_V x^2 dV + y^2 dV + z^2 dV = \int^a_0 \int^b_0 \int^c_0 x^2 dzdydx + \int^a_0 \int^b_0 \int^c_0 y^2 dzdydx + \int^a_0 \int^b_0 \int^c_0 z^2 dzdydx [/itex]<br /> [tex]I = \frac{\rho}{3} ( a^3 bc + ab^3 c + abc^3)[/tex]<br /> [tex]I = \frac{M}{3abc} ( a^3 bc + ab^3 c + abc^3)[/tex]<br /> [tex]I = \frac{M}{3} (a^2 + b^2 + c^2)[/tex]<br /> <br /> This problem looked cool so I did it, but it was an even one so there is no answer in the back of the book. Does this look right?[/tex]
 
Last edited by a moderator:
Physics news on Phys.org
Is this the situation? (red is axis of rotation)
1657047568503.png

If this is the case, the moment of inertia can not depend on c.
There is another, simpler, shape that you can use instead...
 
The classical mistake when calculating MoIs: ##r## should not be the magnitude of the position vector of the element dV, but its distance perpendicularly to the axis of rotation.
 
Reply
  • Like
Likes   Reactions: Orodruin and malawi_glenn
drmalawi said:
Is this the situation? (red is axis of rotation)
View attachment 303793
If this is the case, the moment of inertia can not depend on c.
There is another, simpler, shape that you can use instead...
Just to add a side note: This depends on what is considered given. If the density is known and fixed, then the MoI will depend on c because larger c means more mass. If the density is instead adjusted such that the total mass ##M## is known, then indeed the MoI will be independent of c.
 
Reply
  • Like
Likes   Reactions: Delta2 and malawi_glenn
Orodruin said:
This depends on what is considered given
That's true, the c-dependece will show up in M if a fixed density is given (also M would have a and b dependence M = ρabc)