Calculating Sag & Tension for 2 Wires: 5000 lbs Horizontal Tension

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SUMMARY

This discussion focuses on calculating the sag and tension of two wires with a horizontal tension of 5000 lbs. The sag of a single wire can be determined using the formula: Sag = (W*L^2)/(8*T), where W represents the weight of the wire, L is the span between supports, and T is the horizontal tension. For the two-wire scenario, the weights are .65 lbs/ft for the first wire and 7.8 lbs/ft for the second wire. The discussion emphasizes the need to account for the initial wire's weight when calculating the new sag and tension for the combined wire system.

PREREQUISITES
  • Understanding of basic physics principles related to tension and sag in cables
  • Familiarity with the parabolic shape of hanging wires under uniform load
  • Knowledge of the equation for sag calculation: Sag = (W*L^2)/(8*T)
  • Basic grasp of weight measurements in lbs/ft
NEXT STEPS
  • Research the effects of temperature on wire tension and sag
  • Learn about the catenary curve and its application in wire tension calculations
  • Explore methods for combining weights of multiple wires for sag calculations
  • Investigate software tools for simulating wire tension and sag scenarios
USEFUL FOR

Engineers, physicists, and construction professionals involved in structural design and analysis of cable systems will benefit from this discussion.

epena
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I'm trying to figure out the sag of a wire hanging between two objects. If I string a wire between two structures and tension the wire 5000 lbs in the horizontal direction, I can estimate the shape of the wire to be parabolic and use the equation: Sag = (W*L^2)/(8*T), where W=Weight of wire, L=Span between two supports, and T=Horizontal Tension to calculate the sag. If now I add a much heavier wire to the first wire, how can I arrive at the new Sag and Tension for the two wire combination? I am assuming the same temperature for both installations (60 degrees F). The first wire is .65 lbs/ft; the second wire is 7.8 lbs/ft. I am trying to solve the problem without neglecting the initial wire's weight.
 

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Have a look at this

http://mathworld.wolfram.com/Catenary.html

If two different wires hang in the same curve they must be joined along their length, so you can pretend it's one wire with the average density (?)
 

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