Calculating Shaft Size for 100 Nm of Torque

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Discussion Overview

The discussion revolves around calculating the appropriate shaft size for a given torque of 100 Nm, with considerations for the moment of inertia, angular velocity, and material properties. Participants explore various factors that influence shaft sizing in mechanical systems.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant requests additional information about the force applied or the length of the shaft to assist in the calculation.
  • Another participant provides details about a rotating shaft with a disc, specifying a moment of inertia and desired speed and acceleration, leading to a calculated torque of 101.5 Nm.
  • A suggestion is made to determine the yield stress of the shaft material and use it in the equation for maximum shear stress to find the diameter, emphasizing the need for a safety factor.
  • One participant questions the torque calculation, suggesting that with the provided values, the torque should be around 32 Nm, indicating a potential misunderstanding or error in the initial calculations.
  • Links to manufacturer tables for shaft sizing are shared as a resource for determining appropriate shaft dimensions.
  • A participant questions whether knowing the moment of inertia implies that the dimensions of the system have already been determined, suggesting a formula to find the necessary dimensions based on the moment of inertia.
  • Another participant notes that if the final velocity and acceleration are known, the time of acceleration can be calculated, which may be relevant to the discussion.

Areas of Agreement / Disagreement

Participants express differing views on the calculations and assumptions regarding torque and shaft sizing, indicating that multiple competing perspectives remain without a clear consensus.

Contextual Notes

Some assumptions about material properties and safety factors are not explicitly stated, and there are unresolved questions regarding the calculations of torque and the relationship between dimensions and moment of inertia.

Shady99
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hello i have a torque of 100 Nm. how to calculate the shaft size?
 
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Shady99 said:
hello i have a torque of 100 Nm. how to calculate the shaft size?
I would love to help you but you need to either provide information on how much force you are applying or how long the shaft is, with the latter assumed to be the question. It may also help to give some context, what scenario is this shaft and torque in?
 
I have a rotating shaft wiht a disc on top of it .The moment of inertia of the system is 185 kgm2.i would like the system to attain a speed of 35 deg/sec with an acceleration of 10 deg/sec2. so the torque comes out to be 101.5 Nm. Now what should be the shaft diameter?
 
You need to know the yield stress of material of your shaft. Then you insert this value to equation for maximum sheer stress (assuming you have pure torsion). This should give you the value of diameter which will cause your shaft to get on the edge of yielding. Used diameter should be bigger than this. How much bigger depends on requested safety factor.

By the way, if I remember correctly, relation between torque and angular acceleration is given as T=J*α (T - torque, J - moment of inertia, α - angular acceleration in rad/sec2).
With your values, it gives T about 32 Nm. Or am I missing something ?
 
Shady99 said:
I have a rotating shaft wiht a disc on top of it .The moment of inertia of the system is 185 kgm2.i would like the system to attain a speed of 35 deg/sec with an acceleration of 10 deg/sec2. so the torque comes out to be 101.5 Nm. Now what should be the shaft diameter?
A couple of questions here:
If you know the moment of inertia of the whole system, doesn't that mean that you have figured out the dimensions of the system? If I am given those information, I would use the formula here:
http://hyperphysics.phy-astr.gsu.edu/hbase/icyl.html
to figure out what combination of dimensions will have that value.

On the angular velocity and angular acceleration part, I am not sure what is the unknown here, if you know the final velocity and acceleration, what you can find is time of acceleration, in this case it would take 3.5seconds.
 

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