Calculating Speed from Acceleration and Time

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SUMMARY

The discussion centers on calculating speed from acceleration and time, specifically using the formula v = u + at. A user inquires whether multiplying the acceleration of 3.47 m/s² by 5 seconds yields the correct speed after that duration. The correct calculation confirms that the speed after 5 seconds is indeed 17.4 m/s, assuming the car starts from rest. The importance of understanding initial conditions in kinematic equations is emphasized.

PREREQUISITES
  • Understanding of kinematic equations, specifically v = u + at
  • Knowledge of acceleration units (m/s²)
  • Familiarity with speed and velocity concepts
  • Basic grasp of physics principles related to motion
NEXT STEPS
  • Study the implications of initial conditions in kinematic equations
  • Learn about different types of acceleration (constant vs. variable)
  • Explore real-world applications of kinematic equations in automotive physics
  • Investigate the relationship between speed, distance, and time in motion analysis
USEFUL FOR

Students studying physics, automotive engineers, and anyone interested in understanding motion dynamics and kinematic calculations.

wakejosh
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can I just multiply 3.47 m/s/s by 5 seconds to get my speed after that amount of time? for example:

. A European sports car dealer claims that his car will accelerate
at a constant rate from rest
to a speed of 100 km/hr (28 m/s) in 8.00 s. What is the speed
after the first 5.00 s of
acceleration?

a.44.4 m/s b. 34.7 m/s c. 28.7 m/s d. 17.4 m/s e. 8.7
m/s


First I find the acceleration to be 3.47 m/s^2 now can i just times by 5? If so i get 17.4 m/s Is this correct?
 
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yes that is correct

if u are in doubt you can always look at what you're given and your kinematic equations to get your answer
 
v=u+at
You are right in this context but make sure you have an accurate bearing of your question. It would not have been correct if the car did not start from rest.
 

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