- #1

matematikuvol

- 192

- 0

\hat{\rho} = \begin{bmatrix}

\frac{1}{3} & 0 & 0 \\[0.3em]

0 & \frac{1}{3} & 0 \\[0.3em]

0 & 0 & \frac{1}{3}

\end{bmatrix}

[/tex]

If I have this statistical operator I get

[tex]i\hbar\frac{d\hat{\rho}}{dt}=0[/tex]

So this is integral of motion and

[tex][\hat{H},\hat{\rho}]=0[/tex]

Is this correct? Tnx for your answer.