Calculating Stream Width from AB to Point C | Law of Sines Application

  • Thread starter Thread starter FawkesCa
  • Start date Start date
Click For Summary
SUMMARY

The discussion centers on calculating the width of a stream using the Law of Sines, given a line segment AB of 652 feet and angles A (53° 18') and B (48° 36'). Multiple participants confirmed a calculated width of approximately 400.74 feet, while the answer book states it should be 345.45 feet. The discrepancy arises from potential misinterpretation of the angles involved in the triangle formed by points A, B, and C. Participants emphasized the importance of verifying calculations and seeking clarification from instructors when faced with conflicting results.

PREREQUISITES
  • Understanding of the Law of Sines
  • Basic trigonometric functions (sine, cotangent)
  • Ability to interpret geometric diagrams and angles
  • Familiarity with triangle properties and calculations
NEXT STEPS
  • Review the Law of Sines and its applications in triangle calculations
  • Practice problems involving angle and side relationships in triangles
  • Learn about common trigonometric errors and how to avoid them
  • Consult resources on geometric interpretation of trigonometric functions
USEFUL FOR

Students studying trigonometry, educators teaching geometry, and anyone involved in practical applications of trigonometric calculations in engineering or physics.

FawkesCa
Messages
43
Reaction score
0
for God's sake...I NEED HELP!

Homework Statement


AB is a line 652 feet long on one bank of a stream, and C is a point on the opposite bank. A = 53° 18', and B = 48° 36'. Find the width of the stream from C to AB.


Homework Equations



law of sines

The Attempt at a Solution


ive proven all variables are correct (A,B,C and a, b, c). i come up with a height of 400.74ft. the answer book says its 345.45ft.
ive done this 6 times and come up with the same answer. am i a retard or should i just not go to Clark University (its their website)
 
Physics news on Phys.org


I'm also getting the same answer as you, if you let the two angles be \alpha,\beta and the distance across the bank be d, then the width of the river is given by

w=\frac{d}{cot(\alpha)+cot(\beta)}

and plugging in your values gives approx 400ft.
 


I get the same answer as the OP as well. But there is some ambiguity as to what the angles are. The "A = some angle" and "B = some angle" statements really don't make sense, since A and B are just corners of the triangle. I assumed that "A" actually meant angle CAB, and that "B" actually meant angle CBA.
 


Likewise, 400.739 ft., by

w = \frac{d \; \sin(\beta) \; \sin(\alpha)}{\sin(180^{\circ}-\alpha-\beta)}
 


\sin(180^{\circ}-\alpha-\beta)=\sin(\alpha+\beta) :smile:
 


Ooh, so it is. Goodbye pi! So long, minuses!
 


And with a little re-arrangement, bring on the cotangents that I used! :biggrin:
 


thank you, thank you, THANK YOU! i guess clark university is not the best place to try and teach yourself trigonometry. all of you help me SOOOOOOO much.
 


FawkesCa said:
i guess clark university is not the best place to try and teach yourself trigonometry.

Not necessarily. Pretty much every book is going to have a few typos in it, you just need to be prepared. If you are getting a different answer and are sure of yourself, then don't be so quick to disbelieve your own work. Leave it and ask your professor or here online.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 8 ·
Replies
8
Views
5K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 2 ·
Replies
2
Views
8K
  • · Replies 28 ·
Replies
28
Views
5K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 23 ·
Replies
23
Views
3K
  • · Replies 3 ·
Replies
3
Views
9K