Law of Sines problems that involve a perpendicular

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Homework Help Overview

The discussion revolves around problems involving the Law of Sines, particularly in the context of triangles with perpendiculars. Participants are attempting to solve for distances and angles in two specific triangle scenarios involving a stream and a point across from it.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants are exploring the use of the Law of Sines and discussing the implications of perpendiculars on their calculations. There are attempts to derive lengths and angles based on given angles and sides, with some questioning the accuracy of their results.

Discussion Status

Some participants have provided calculations and alternative approaches, while others express confusion about specific steps and results. There is an acknowledgment of potential errors in function usage and a discussion about the reliability of provided answers in reference materials.

Contextual Notes

Participants mention that the problems are not strictly homework questions but rather a re-learning effort, indicating a desire to understand the underlying concepts better. There is also a reference to rounding differences in calculations.

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Could someone point me in the correct direction? I have no problem working out the angles and lines, but when one has to take into account the perpendicular, then I get confused. It is clear that the relationships are altered, but I am missing something? I have made worked further in the problem set but these two have me a bit mixed up. These are from a website, and as I have related I am trying to re-learn old math habits. Not a "homework" question, per se.

Homework Statement



AB is a line 652 feet long on one bank of a stream, and C is a point on the opposite bank. A = 53° 18', and B = 48° 36'. Find the width of the stream from C to AB.

In a triangle ABC, a = 700 feet, B = 73° 48', and C = 37° 21'. If M is the middle point of BC find the length of AM, and the angles BAM and MAC.

Homework Equations



SinA/a = SinB/b = SinC/c

The Attempt at a Solution



sin 53.3 (652)/sin 78.1 = a, the calculator claims 534.24'
then, cos 48.6 (534.24') = c, calculator reads 353.30' WRONG!

For the second one I worked to this point:

b = sin 73.8 (700')/sin 68.85 = 720.76', then sin 37.35 (720.76) = AM. . .I saw this wasn't correct. . .
 
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For the first problem, I agree that a = 534.24', but I disagree with your final value for the width of the stream. The relationship is sin(48.6 deg) = w/534.24, so w = 534.24 * sin(48.6 deg) = 400.74' (approx).
 
For the second problem, after you have found b, you know MC and angle C, so you can use the law of cosines to find AM.
 
Eureka!

As for the second problem, I now get 490.75'. The answer given is 490.83'. I am thinking that is rounding difference. On the first problem, I have no idea why I used cos instead of sine. . . looking at too many problems, I suppose. However, the given answer is 345.43'. After I correct for my function error, I get the same figure that you do.
 
I don't see how they get 345.43' for the first problem. I worked it again and got 400.74' again. It's possible that the book's answer is wrong. I don't automatically assume that when my answer is different from the book's answer, but answers in books are wrong from time to time.
 

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