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Law of Sines problems that involve a perpendicular

  1. Apr 18, 2009 #1
    Could someone point me in the correct direction? I have no problem working out the angles and lines, but when one has to take into account the perpendicular, then I get confused. It is clear that the relationships are altered, but I am missing something? I have made worked further in the problem set but these two have me a bit mixed up. These are from a website, and as I have related I am trying to re-learn old math habits. Not a "homework" question, per se.

    1. The problem statement, all variables and given/known data

    AB is a line 652 feet long on one bank of a stream, and C is a point on the opposite bank. A = 53° 18', and B = 48° 36'. Find the width of the stream from C to AB.

    In a triangle ABC, a = 700 feet, B = 73° 48', and C = 37° 21'. If M is the middle point of BC find the length of AM, and the angles BAM and MAC.

    2. Relevant equations

    SinA/a = SinB/b = SinC/c

    3. The attempt at a solution

    sin 53.3 (652)/sin 78.1 = a, the calculator claims 534.24'
    then, cos 48.6 (534.24') = c, calculator reads 353.30' WRONG!

    For the second one I worked to this point:

    b = sin 73.8 (700')/sin 68.85 = 720.76', then sin 37.35 (720.76) = AM. . .I saw this wasn't correct. . .
     
    Last edited: Apr 18, 2009
  2. jcsd
  3. Apr 18, 2009 #2

    Mark44

    Staff: Mentor

    For the first problem, I agree that a = 534.24', but I disagree with your final value for the width of the stream. The relationship is sin(48.6 deg) = w/534.24, so w = 534.24 * sin(48.6 deg) = 400.74' (approx).
     
  4. Apr 18, 2009 #3

    Mark44

    Staff: Mentor

    For the second problem, after you have found b, you know MC and angle C, so you can use the law of cosines to find AM.
     
  5. Apr 18, 2009 #4
    Eureka!

    As for the second problem, I now get 490.75'. The answer given is 490.83'. I am thinking that is rounding difference. On the first problem, I have no idea why I used cos instead of sine. . . looking at too many problems, I suppose. However, the given answer is 345.43'. After I correct for my function error, I get the same figure that you do.
     
  6. Apr 18, 2009 #5

    Mark44

    Staff: Mentor

    I don't see how they get 345.43' for the first problem. I worked it again and got 400.74' again. It's possible that the book's answer is wrong. I don't automatically assume that when my answer is different from the book's answer, but answers in books are wrong from time to time.
     
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