Calculating String Tension for Hanging Picture (50N)

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Homework Help Overview

The discussion revolves around calculating the tension in a string used to hang a picture, with the weight of the picture specified as 50N and the string forming a 40-degree angle with the horizontal. Participants are exploring the principles of forces acting on the picture and how to analyze them.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants suggest drawing a free body diagram to visualize the forces involved. There are discussions about applying Newton's Laws and resolving vectors into components. Some participants express confusion about the notation used for vector representation and question its appropriateness.

Discussion Status

The discussion is active, with participants offering various perspectives on how to approach the problem. Some guidance has been provided regarding the use of free body diagrams and the concept of tension, but there is no explicit consensus on the best method to solve the problem. Several interpretations of the forces at play are being explored.

Contextual Notes

Some participants indicate that they have not yet covered the topic of tension in their coursework, which may limit their understanding of the problem. There is mention of a lack of prior exposure to free body diagrams and related formulas in their studies.

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I need to work out the tension in a piece of string when hanging a picture off one nail on the wall. All I know is that the weight of the picture is 50N and the angle of the sides of the string are at a 40 degree angle from the top of the picture. I have no idea of even how to start working this out. Can anyone help?
 
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I would begin by drawing a free body diagram labelling all the forces and their orientations.
 
Energize said:
I need to work out the tension in a piece of string when hanging a picture off one nail on the wall. All I know is that the weight of the picture is 50N and the angle of the sides of the string are at a 40 degree angle from the top of the picture. I have no idea of even how to start working this out. Can anyone help?

Draw a force diagram
Apply Newton's Laws

Realize that the picture is not moving, thus it's velocity is zero. Newton's law will drop down to:

[tex]\sum \vec F_i = 0[/tex]

Remember that you can write a vector as:
[tex]\vec T = \hat T |\vec T|[/tex]

or in a more familiar notation,
[tex]\vec T = \hat i \, T \cos \theta + \hat j \, T \sin \theta[/tex]

does that help?

hint: you will need to solve for T
 
Are you familiar with free body diagrams, which show all the forces on objects? Does you textbook have a similar examples worked out for you where there are cables or strings involved?

EDIT -- Oops, I was too slow!
 
Um, I disagree with this:

[tex]\vec T = \hat i \, T \cos \theta + \hat j \, T \sin \theta[/tex]

This is bad practice and should be avoided.
 
The only force acting on it is gravity, our class hasn't drawn any of these diagrams you speak of or seen that formulae before, I've just started AS and our teacher just gave us this sheet with loads of questions on without even teaching us about tension yet.

/\
/ \
/ \
/40o 40o\
------------
| |
| |
--------------
50 Newtons
 
Last edited:
Energize said:
The only force acting on it is gravity, our class hasn't drawn any of these diagrams you speak of or seen that formulae before, I've just started AS and our teacher just gave us this sheet with loads of questions on without even teaching us about tension yet.
See if this info from wikipedia helps:

http://en.wikipedia.org/wiki/Free_body_diagram
 
cyrusabdollahi said:
Um, I disagree with this:

[tex]\vec T = \hat i \, T \cos \theta + \hat j \, T \sin \theta[/tex]

This is bad practice and should be avoided.

Yeah, I posted that rather quickly. I disagree with it too.

I should have just said something along the lines of resolving the vector into its components via the angle between them. Because what I wrote only holds for a subset of problems.

Do you think I should edit it out?

On a side note, I personally hate the [itex]\hat i, \,\, \hat j \,\, \hat k[/itex] notation.
 
Energize said:
The only force acting on it is gravity, our class hasn't drawn any of these diagrams you speak of or seen that formulae before, I've just started AS and our teacher just gave us this sheet with loads of questions on without even teaching us about tension yet.

/\
/ \
/ \
/40o 40o\
------------
| |
| |
--------------
50 Newtons

If the only force acting on it was gravity it would continue to fall forever in the direction of the gravity vector.

Imagine a balloon hovering in the air. What forces act on it?
Well of course gravity does.
Then the helium in the balloon is trying to rise which creates an upwards force right?

Well since the balloon is hovering (ie not moving) the "helium" upward force, and the gravity downward force must be equal. You can think of that "helium" force as the force applied to the string. That force is the tension.

Does that makes sense?
 
  • #10
FrogPad said:
Yeah, I posted that rather quickly. I disagree with it too.

I should have just said something along the lines of resolving the vector into its components via the angle between them. Because what I wrote only holds for a subset of problems.

Do you think I should edit it out?

On a side note, I personally hate the [itex]\hat i, \,\, \hat j \,\, \hat k[/itex] notation.

Nah, so long as he knows its not a 'formula'
 

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