Calculating Student Power: P=W/T Equation Explained | 60kg Lift in 4 Seconds"

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Homework Help Overview

The discussion revolves around calculating the power exerted by a student lifting a 60kg weight to a height of 2.5 meters in 4 seconds, utilizing the equation P=W/T.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster expresses uncertainty about using the P=W/T equation, noting that work is an unknown variable. Participants discuss the force due to gravity and its role in calculating work and power.

Discussion Status

Participants are exploring the relationship between force, work, and power, with some providing clarifications on the calculation of gravitational force. There is an ongoing examination of the assumptions related to gravitational force and its implications for the problem.

Contextual Notes

There is a mention of the gravitational constant and its variability depending on the planetary context, which may influence the calculations.

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Homework Statement


How powerful is a student who can lift 60kg from the floor to above their head (2.5 meters from the ground) in 4 seconds?


Homework Equations


To find power we would use the equation
P= W/T

The Attempt at a Solution


I'm not sure if we would use the P=w/t equation, and work is an unknown variable, and when I try to find W, W=FxD, Force is also an unknown variable
 
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What is the force on the object due to gravity (this would also be the force required to lift it)?
 


Would the force on the object due to gravity be 9.8N
so the Force required to lift it is 9.8 N
 


Force due to gravity is mg. Then use that and the distance to find the work, and the work and the time to find the power.
 
Last edited:


Keep in mind that the force by gravity is not 9.8 N but rather m(9.8 m/s^2) where 9.8 = g. This would be different if we were on a planet other than our homely earth.
 

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