Calculating tangential acceleration of rotating object

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To determine the average tangential acceleration of the tire, the key equations involve the relationship between linear and rotational motion, specifically a = α * r. The user struggles to eliminate the radius from their calculations while trying to convert rotational acceleration (α) to linear acceleration (a). They are encouraged to post their working to identify any missed information or equations. The discussion emphasizes the importance of utilizing all given data to solve for the linear acceleration of the ant. Understanding the conversion between rotational and linear parameters is crucial for solving the problem effectively.
APphysicsSenior
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Homework Statement


An ant clings to the outside edge of the tire of an exercise bicycle. When you start pedaling, the an't speed increases from ) to 10 m/s in 2.6 s. The wheel's rotational acceleration is 13 rad/s^s.

Determine the average tangential acceleration of the tire.

Homework Equations


v=ω*r
a=∝*r
v=Δx/Δt
a=Δv/Δt
ω=ΔΘ/Δt
∝=Δω/Δt

The Attempt at a Solution


I tried to manipulate the formulas that involved ∝, v and t in order to solve for a, but I couldn't get the radius to cancel out, or I kept ending up with ω in the equation. I need help figuring out how to convert rotational acceleration (∝) to linear acceleration (a) WITHOUT the radius.
 
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Maybe you can find the radius from what is already given. Can you find the linear acceleration of the ant from what is given?
 
APphysicsSenior said:
That is the "is proportional to" symbol. What you mean is α (alpha).
APphysicsSenior said:
tried to manipulate the formulas
Please post your working. Check whether you used all the given information. If you did not, try to find an equation that involves the information you did not use.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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