Calculating Tension Force in a Tug-of-War

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In a tug-of-war scenario where person A is winning, the tension force for person B is suggested to be 900 N, based on the assumption that tension is constant throughout a massless rope. The discussion emphasizes that if the rope is massless, the tension remains the same regardless of acceleration. If the rope had mass, the tension could vary, but it is typically assumed to be negligible. The conversation also touches on the implications of acceleration on tension, noting that if person A is winning, the rope would be accelerating unless at a constant velocity. Overall, the key point is that the tension force remains constant in this idealized scenario.
temaire
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Homework Statement


The diagram below shows two people having a tug-of-war. Determine the unknown tension force if person A is winning.

http://img80.imageshack.us/img80/8286/forcefp2.gif​


Homework Equations


None that I think are necessary.


The Attempt at a Solution


I think that the unkown tension for person B would be 900 N, because tension is constant throughout the entire rope.
 
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You're right if the rope is massless... do they give a mass for the rope?
 
temaire said:

Homework Equations


None that I think are necessary.

How about Fnet = ma?

temaire said:

The Attempt at a Solution


I think that the unkown tension for person B would be 900 N, because tension is constant throughout the entire rope.

Typically, since the mass of the rope is negligible compared to the rest of the system we assume it to be massless. If so, then the tension throughout the rope is indeed the same (of course if it has mass and is not accelerating then you get the same result as well).

In this case, since A is winning, the rope would be accelerating (unless A is winning at a constant velocity!). However, since the rope is assumed massless then the tension is the same throughout as previously stated.
 
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No, they don't give a mass for the rope. Thanks for the help though guys.
 
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