Calculating Tension in a Hanging Mass: 15 and 25 Degree Angles

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The discussion focuses on calculating the tension in a clothesline supporting a 12 kg mass, with angles of 15 degrees and 25 degrees on either side. The equations derived include T1sin(15) + T2sin(25) = 117.6N and T1cos(15) = T2cos(25). The correct approach involves substituting the sine and cosine values into these equations to solve for the tensions T1 and T2 using algebraic methods. The clarification provided emphasizes the importance of accurately applying trigonometric functions in the equations.

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this is probably really easy but i can't get it

a 12kg mass is hanging from a clothes line. the line on the left forms an angle of 15 degrees and the angle of the line on the right forms a 25 degree angle. i have to solve for the tension on both sides of the clothesline

i drew a free body diagram and two diagrams showing the components of tension but i still can't solve it this is what i came up with so far

T1sin15 + T2Sin25 = 117.6N

T1cos15 = T2cos15
 
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cashslash89 said:
this is probably really easy but i can't get it

a 12kg mass is hanging from a clothes line. the line on the left forms an angle of 15 degrees and the angle of the line on the right forms a 25 degree angle. i have to solve for the tension on both sides of the clothesline

i drew a free body diagram and two diagrams showing the components of tension but i still can't solve it this is what i came up with so far

T1sin15 + T2Sin25 = 117.6N

T1cos15 = T2cos15
Yes, that looks almost right, but you meant T2cos25 in that last equation, I think. Now it's just algebra...plug in the numeric sin and cos values, and you have 2 equations and 2 unknowns, you should be able to solve for T1 and T2 using the algebraic method of your choice.
 
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