Calculating Tension in an Elevator Cable - Is My Solution Correct?

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SUMMARY

The discussion centers on calculating the tension in an elevator cable supporting a cabin with a total mass of 747 kg, which includes the cabin's mass of 567 kg and an additional 180 kg of passengers. The cable exerts a constant upward acceleration of 6 m/s². Using Newton's second law, the tension T is calculated as T = ma + mg, resulting in a tension of 11,810.07 N. The solution presented is confirmed as correct based on the provided calculations.

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  • Basic knowledge of forces including tension and gravitational force
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Homework Statement



Here is the statement :
An elevator cabin of mass 567 kg combine a mass of people inside the cabin of 180 kg.The cabin is pulled upward by a cable with a constant acceleratuon of 6 m/s².
What is the tension T of the cable

Homework Equations



I used the second law of Newton :
Fnet = ma
with m = 567 + 180 = 747

The Attempt at a Solution



so T+ Fg = ma
and T= ma+ mg
so T= 11810.07 N

IS IT CORRECT ??
 
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Looks OK.
 

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