Calculating Tension in an Elevator Cable - Is My Solution Correct?

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Homework Statement



Here is the statement :
An elevator cabin of mass 567 kg combine a mass of people inside the cabin of 180 kg.The cabin is pulled upward by a cable with a constant acceleratuon of 6 m/s².
What is the tension T of the cable

Homework Equations



I used the second law of Newton :
Fnet = ma
with m = 567 + 180 = 747

The Attempt at a Solution



so T+ Fg = ma
and T= ma+ mg
so T= 11810.07 N

IS IT CORRECT ??
 
on Phys.org
Looks OK.
 

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