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WOLFY302

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**A 30 kg sphere is held stationary by two cables. One cable is attached at 60° above horizontal. The second cable is horizontal and attached at the side of the sphere. Find the tension in both cables.**

Newton's 2nd law: F=ma, which means a = (∑F/m)

We can also find the weight: W = mg

Let's say that the tension for the angled cable is T

_{1}and the tension for the horizontal cable is T

_{2}. Weight is mg, or (30 kg)(9.8 m/s^2). Acceleration is zero since the sphere is stationary, which means 0 = (∑F/m).

I'm not sure what to do from here. Any help would be greatly appreciated.

Thanks in advance.

WOLFY