Calculating Tension in an Inclined Plane Problem

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SUMMARY

The discussion focuses on calculating the tension in a rope required to pull a 1200-N go-cart up a 25-degree incline at a constant speed, with the rope making a 35-degree angle with the horizontal. The initial calculation incorrectly treated the angle of the rope relative to the incline, leading to an erroneous tension value of 618.46 N instead of the correct 515 N. The key takeaway is the importance of accurately interpreting angles in inclined plane problems to determine forces correctly.

PREREQUISITES
  • Understanding of basic physics concepts, specifically forces and tension.
  • Familiarity with trigonometric functions, particularly sine and cosine.
  • Knowledge of inclined plane mechanics.
  • Ability to solve right triangle problems using trigonometry.
NEXT STEPS
  • Study the principles of inclined plane mechanics in detail.
  • Learn how to apply trigonometric functions to solve for unknown forces in physics problems.
  • Explore examples of tension calculations in various contexts, including frictionless scenarios.
  • Review common mistakes in interpreting angles in physics problems and how to avoid them.
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone involved in mechanics or engineering who seeks to understand the dynamics of forces on inclined planes.

BrainMan
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Problem: a 1200-N go-cart is being pulled up a 25 degree incline by a rope that makes an angle of 35 degrees with the horizontal. Neglecting all frictional effects, determine the tension in the rope necessary to pull the cart up the incline at a constant speed

Relevant equations:
Sum of the forces= 0

Attempt: The first thing I did was find the force necessary to pull the cart at a constant speed parallel to the horizontal so sin 25= x/1200 so x= 507.14. Then I treated that number like one of the sides of a right triangle and did Cos 35= 507.14/x and got x= 618.46. The correct answer is 515 N
 
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I think you treated it like the rope was at an angle of 35 degrees relative to the cart. Actually it is only 10 degrees.
 
Ok I see my mistake. Thanks!
 

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