Calculating Terminal Speed of a 82kg Skydiver using Basic Physics Formulas

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Steelers72
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Homework Statement


A 82kg skydiver can be modeled as a rectangular "box" with dimensions 21cm× 44cm× 1.8m

Homework Equations


v = sqrt(2mg/(rho * C *A))

The Attempt at a Solution



A = 0.21 m * 0.44 m = 0.0924 m^2

v = sqrt(2 * 82 kg * 9.81 m/s^2 / (1.2 kg/m^2 * 0.0924 m^2 * 0.80))
=135m/sApparently this is wrong. I have tried many other formulae but I haven't had luck and I have one more attempt remaining. Any ideas?
 
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Svein said:
Why are you assuming that he dives "head first"?

the question doesn't suggest otherwise, doesn't specify if he dives head first or legs first.
 
Steelers72 said:
the question doesn't suggest otherwise, doesn't specify if he dives head first or legs first.

What if the skydiver takes this attitude, before the parachute opens?

freefall2.jpg
 
SteamKing said:
What if the skydiver takes this attitude, before the parachute opens?

freefall2.jpg

Agreed! Take the largest surface of the box as area.