- #1

kgianqu2

- 16

- 0

A)What is the y component of vector A?

B)What is the magnitude of vector A?

I got -13.0m for part a, and 19.8m for part b, but mastering physics says they are wrong. Any ideas?

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- Thread starter kgianqu2
- Start date

- #1

kgianqu2

- 16

- 0

A)What is the y component of vector A?

B)What is the magnitude of vector A?

I got -13.0m for part a, and 19.8m for part b, but mastering physics says they are wrong. Any ideas?

- #2

Nessdude14

- 172

- 2

- #3

kgianqu2

- 16

- 0

I thought this method would work, and I am not sure where I went wrong.

- #4

kgianqu2

- 16

- 0

Correction: my first post should say, 41 degrees clockwise from the -y-axis)

- #5

Muphrid

- 834

- 2

If the tangent is greater than 1, how can the y component be smaller than the x component?

- #6

Nessdude14

- 172

- 2

[itex]\displaystyle tan(229°)=\frac{A_y}{A_x}[/itex]

[itex]\displaystyle A_y=A_x tan(229°)[/itex]

and you're claiming that:

[itex]\displaystyle A_y=-15 tan(229°)=-13.0[/itex]

right? however, I get:

[itex]\displaystyle A_y=A_x tan(229°)=-17.25[/itex]

You should try re-calculating your value for A

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