Why doesn't this force give the gravitational acceleration on the surface of the earth?(adsbygoogle = window.adsbygoogle || []).push({});

[tex]a = G \cdot \frac{m}{r^2}[/tex]

I would think that it could be derived from the law of universal gravitation:

[tex]F = G \cdot \frac{m_1 \cdot m_2}{r^2}[/tex]

Since [tex]F = m_2 a[/tex]

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# Calculating the gravitational accelleration on the surface of a planet

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