Calculating the Horizontal Force for Stationary Blocks on a Cart

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SUMMARY

The discussion focuses on calculating the horizontal force required to keep blocks stationary on a frictionless cart. The equations derived include T = m(1)*a and m(2)*g - T = m(2)*a, leading to the acceleration formula a = F / [M + m(1) + m(2)]. The final expression for the force F is given as F = m(2)*g*[M+m(1)+m(2)] / m(1), which corrects the initial attempt by ensuring the proper relationship between the masses and the acceleration. The clarification emphasizes that the vertical acceleration of m(2) differs from the horizontal acceleration of m(1).

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Homework Statement



What horizontal force must be applied to the cart (of mass M) shown in Figure P5.67 so that the blocks remain stationary relative to the cart? Assume all surfaces, wheels, and pulley are frictionless. Notice that the force exerted by the string accelerates m(1).

Figure P5.67:
F_P5.67.jpg



Homework Equations



Sum of forces on m(1):

1) T = m(1)*a

2) m(2)*g - T = m(2)*a

3) a = F / [M + m(1) + m(2)]



The Attempt at a Solution



Well, I first created the above equations. I substituted T (from equation 1) into 2), which gave me:

a = [m(2)*g] / [m(1) + m(2)]

I then subbed this into equation 3, which gave me:

F = m(2)*g*[M+m(1)+m(2)] / [m(1) + m(2)]


The book's answer is nearly the same thing, except that it's only m(1) in the denominator:

F = m(2)*g*[M+m(1)+m(2)] / m(1)






Thanks in advance for the help :)


Taylor
 
Physics news on Phys.org
The magnitude of the acceleration of m2 vertically with respect to the ground is NOT the same as the magnitude of the acceleration of m1 horizontally with respect to the ground.
 

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