- #1
soandos
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is there a way to determine (does not need to be exact) the number of digits in x! ?
sorry if this is kind of pointless
sorry if this is kind of pointless
soandos said:is there a way to determine (does not need to be exact) the number of digits in x! ?
Gib Z said:Don't forget to then apply
[tex]D = 1 + \lfloor \log_{10} \lfloor n! \rfloor \rfloor [/tex]
after that for the number of digits.
Jarle said:If [tex]n![/tex] is hard to calculate, the series
[tex]D = 1 + \lfloor \sum^n_{i=1} \log_{10}i \rfloor[/tex]
should be easier to calculate - for integer [tex]n[/tex].
To calculate the number of digits in a given number, you can use the logarithm function. The formula for calculating the number of digits in a number x is log10(x) + 1. This will give you the total number of digits, including any decimal places.
If the number has leading or trailing zeros, you can use the same formula as mentioned above, but exclude the zeros from the calculation. For example, if the number is 00234, you would only count the digits 2, 3, and 4, giving you a total of 3 digits.
Yes, you can also calculate the number of digits in a number by converting it to a string and counting the number of characters. However, this method may not work for very large numbers or numbers with decimals.
Yes, you can use the same formula for calculating the number of digits in a non-integer number. The result will include the digits after the decimal point as well.
To calculate the number of digits in a negative number, you can first remove the negative sign and then use the same formula as mentioned above. The result will be the same as the number of digits in the positive version of the number.