Calculating the Probability of K=3 When Flipping a Coin 6 Times

  • Context: Undergrad 
  • Thread starter Thread starter ParisSpart
  • Start date Start date
Click For Summary

Discussion Overview

The discussion revolves around calculating the probability of obtaining exactly 3 crowns when flipping a biased coin 6 times, where the probability of getting a crown is 0.3. Participants explore different methods to approach the problem, including the use of binomial distribution and complementary counting.

Discussion Character

  • Mathematical reasoning
  • Debate/contested
  • Homework-related

Main Points Raised

  • One participant states the problem of calculating P(K=3) when flipping a coin 6 times with a crown probability of 0.3.
  • Another participant suggests calculating the probability of not getting 3 crowns and subtracting that from 1, listing scenarios for 0, 1, and 2 crowns.
  • A participant questions how to estimate the probabilities for 2 and 3 crowns using combinations.
  • There is a correction regarding the initial misunderstanding of the number of crowns, clarifying that the goal is to find P(K=3) specifically.
  • Some participants express uncertainty about the correctness of the calculations presented, indicating that results may not align with expectations.
  • A later reply emphasizes that the previous answers calculated P(K>=3) instead of P(K=3), highlighting a potential misunderstanding in the approach.
  • One participant eventually claims to have found the correct answer, thanking another for assistance.

Areas of Agreement / Disagreement

Participants express disagreement regarding the correct approach to calculating P(K=3), with some methods being challenged and corrections made. The discussion remains unresolved in terms of a definitive solution, as multiple viewpoints and methods are presented.

Contextual Notes

There are limitations in the clarity of the calculations and assumptions made regarding the binomial distribution and the specific probabilities involved. Some participants may have misunderstood the problem's requirements, leading to confusion in the calculations.

ParisSpart
Messages
129
Reaction score
0
flipping a coin 6 times and let K be the number of crowns that we have after flipping the coin 6 times. The coin has a probability of 0.3 to get the crown.

P(K=3)=?

if we flip the coin 6 times we will have 31 crowns but how i can estimate this series of crowns?
 
Physics news on Phys.org
To achieve three here's what you do:

the easy way is to calaulate when we don't achieve three crowns and then subtract 1 from it.

We might not have three crowns if:
1. there was none. which is 0.7^6
2. there was just one crown which is: {6\choose 1} *0.3*0.7^5
3. there were only two crowns which is {6\choose 2} *0.3^2 * 0.7^4
 
i will sum this? how i can estimate 2 and 3 with nCk ?
 
i did it but its says that the result its not correct ...
 
ParisSpart said:
if we flip the coin 6 times we will have 31 crowns but how i can estimate this series of crowns?

I think you mean "...we will have 3 crowns...".

You will have 3 crowns after flipping a coin 6 times in (6 choose 3) different ways, right? And you get a crown with probability p = 0.3, which implies that you will not have a crown with probability q = 1-p = 0.7. Suppose one of the experiments results as HHTTTH (which is one of the (6 choose 3) possible ways to get 3 crowns). The probability of getting this result of the experiment is

0.3^3\times 0.7^3

You have to sum these probabilities for all (6 choose 3) ways.

Your question is just an example for the binomial distribution.
 
its not correct...
 
MathematicalPhysicist said:
To achieve three here's what you do:

the easy way is to calaulate when we don't achieve three crowns and then subtract 1 from it.

We might not have three crowns if:
1. there was none. which is 0.7^6
2. there was just one crown which is: {6\choose 1} *0.3*0.7^5
3. there were only two crowns which is {6\choose 2} *0.3^2 * 0.7^4

Your answer finds P(K>=3), but OP asks for P(K=3).
 
ParisSpart said:
its not correct...

Can you give your reasoning? May I ask what your computational result is?
 
i found it finaly thanks for help man.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 18 ·
Replies
18
Views
4K
  • · Replies 41 ·
2
Replies
41
Views
9K
  • · Replies 57 ·
2
Replies
57
Views
7K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K