MHB Calculating the Radius of a Graduated Circle

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The discussion revolves around calculating the radius of a graduated circle based on a problem from Loney's Trigonometry. The key measurements include divisions on the outer rim of 5 minutes of arc and a distance of 0.1 inches between graduations. The correct interpretation of 5' is clarified as 5 minutes of arc, not inches or seconds. The arc-length formula, s = rθ, is suggested for solving the radius with the provided values. The confusion regarding terminology is acknowledged and resolved.
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Hello, I was working problems from a very old trigonometry book, Loney's Trigonometry from 1895. There appears here a problem stating:

The value of the divisions on the outer rim of a graduated circle is 5' and the distance between successive graduations is .1 inch. Find the radius of the circle.

I cannot determine what is meant exactly by a graduated circle, other than that it was a surveying instrument. I am also unsure if the 5' measurement is supposed to mean 5 inches or 5 seconds (I'm thinking the latter). Does anyone have any ideas? Thank you!
 
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The expression 5' refers to 5 minutes of arc, or 1/12 of a degree (since there are 60 minutes of arc in a degree). So, I would use the arc-length formula:

$$s=r\theta$$

You are given $s$ and $\theta$, so you can solve for $r$. :D
 
Ah! Okay. I should have said minutes, not seconds. I get it now. Not sure why I was confused.

Thanks!
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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