- #1

John O' Meara

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My attempt: If x=0 is the present position of the hoops then their center of mass is x_cm = -b/2. I=I1+I2=3*m*(3b)^2 + m*b^2 = 28*m*b^2.

Ug = Ktrans +Krot

4*m*g*b/2 = .5*4*m*v^2 + .5*I*v^2/(-b/2)^2

2*m*g*b = 2*m*v^2 + 2*28*b^2*v^2/b^2

= 2*m*v^2 + 56*m*v^2. Therefore 29*v^2=g*b. Therefore v = (g*b/29)^.5;

Is this the correct answer, if not where did I go wrong? Thanks.