Calculating the Torque to mix a liquid

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SUMMARY

The discussion focuses on calculating the torque required to mix liquid asphalt in a tank measuring 12' 2" in length and 65" in diameter, holding 2000 gallons at a density of 8 lbs per gallon and a viscosity of 8000 CP. The user seeks to determine the torque needed for 8 paddles rotating at 25 RPM, using the Reynolds number formula: Re = 10.7 * D^2 * N * specific gravity / viscosity. For a Reynolds number of 11.0 or less, the torque can be calculated using the formula Torque [inch-pounds] = 6.8x10^-8 * viscosity * N * D^3. The user queries the approach for Reynolds numbers exceeding 1.0.

PREREQUISITES
  • Understanding of fluid dynamics and viscosity concepts
  • Familiarity with the Reynolds number and its significance
  • Knowledge of torque calculations in mechanical systems
  • Experience with mixing technologies and paddle design
NEXT STEPS
  • Research the implications of Reynolds numbers greater than 1.0 on mixing efficiency
  • Explore advanced torque calculation methods for non-laminar flow
  • Learn about the effects of paddle design on mixing performance
  • Investigate the use of computational fluid dynamics (CFD) for mixer design optimization
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Engineers, process designers, and anyone involved in the mixing of viscous fluids, particularly in asphalt and chemical processing industries.

SevenToFive
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There is a tank that is 12' 2" long and 65" in diameter that is capable of holding 2000 gallons of liquid asphalt, which is calculated to be 8lbs per gallon, viscosity is 8000CP. There are 8 paddles in this tank that they want to rotate around 25rpm. The diameter of the paddle arms is 60". How do I calculate the torque needed to "mix" this? Am I on the right path thinking that I need to calculate the Reynolds number by
Re = 10.7 * D^2 * N * specific gravity. / visc,
where N is the rpm, D is the diameter of the mixer. If the if the Reynolds number is 11.0 or less I can use
Torque [inch-pounds] = 6.8x10^-8 * visc * N * D^3 to get my required torque. But what if the Reynolds number is above 1.0?

Thanks for the help everyone.
 
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SevenToFive said:
There is a tank that is 12' 2" long and 65" in diameter that is capable of holding 2000 gallons of liquid asphalt, which is calculated to be 8lbs per gallon, viscosity is 8000CP. There are 8 paddles in this tank that they want to rotate around 25rpm. The diameter of the paddle arms is 60". How do I calculate the torque needed to "mix" this? Am I on the right path thinking that I need to calculate the Reynolds number by
Re = 10.7 * D^2 * N * specific gravity. / visc,
where N is the rpm, D is the diameter of the mixer. If the if the Reynolds number is 11.0 or less I can use
Torque [inch-pounds] = 6.8x10^-8 * visc * N * D^3 to get my required torque. But what if the Reynolds number is above 1.0?

Thanks for the help everyone.
 

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